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irakobra [83]
2 years ago
11

NASA has proposed a mission to one of Jupiter's moons to look for potential signs of life. The spacecraft will have 9,862.5 Joul

es of potential energy when it is 60 meters above the surface. If the spacecraft has a mass of 125 kg, what is the gravitational constant of the moon? (units will be m/s^2)
Biology
1 answer:
iren2701 [21]2 years ago
3 0

Answer: The gravitational constant of the moon is 1.315ms^{-2}

Explanation:

Potential energy is the energy possessed by a body by virtue of its position.

P.E=mgh

where

P.E = potential energy = 9862.5 J

m = mass of object = 125 kg

g =  gravitation constant   = ?

h = height of object = 60 m

Putting the values we get :

9862.5kgm^2s^{-2}=125kg\times g\times 60m

g=1.315ms^{-2}

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2 years ago
Question 8 of 10
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The purpose of control group 2 is to determine if the new drug was a possible method for getting well, i.e., option B.

<h3>What is way of testing medicines?</h3>

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The results of these tests are then submitted to the United States Food and Drug Administration (FDA), which determines whether the treatment is safe enough to be studied in human volunteers.

There are various phases involving discovery, clinical trial, review, and safety monitoring.

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Explanation:

6 0
3 years ago
A woman and a man are both heterozygous for a recessive allele for a rare genetic disease. If they have one child, what is the p
makkiz [27]

Answer:

  • If they have one child, the probability that he or she will be affected is 1/4.
  • If they have two children, the probability that at least one of them will be affected is 7/16.

Explanation:

A cross between two heterozygous Aa individuals will produce the followinf offspring: 1/4 AA, 2/4 Aa and 1/4 aa.

Since the disease is recessive, 1/4 of the offspring will have the <em>aa </em>genotype and 3/4 of the offspring will be unaffected.

Every time they have children new gametes were generated <u>independently</u>.

The probability of having <u>no</u> affected children both times is, according to rules of probability for independent events, 3/4 × 3/4 = 9/16 (it's the probability of having a healthy child the first time multiplied by the probability of having a healthy child the second time).

The probability of having at least one affected child is 1 - probability of no affected children = 1 - 9/16 = 7/16.

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Answer:

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Explanation:

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