Answer:
10
Step-by-step explanation:
2y*3x+46
3x+46=2y
(3x+46)/2=y
3/2x+23=y
y=3/2x+23
Answer:
- -3/13 ≈ -1/4
- -6/11 ≈ -1/2
- -7/9 ≈ -3/4
Step-by-step explanation:
We'll drop all the minus signs, since they don't contribute anything but distraction.
When numerators or denominators are relatively large, changing their value by 1 unit will have a relatively small effect on the value of the fraction. For example, ...
3/13 ≈ 3/12 = 1/4
If we compare the decimal values of these fractions, we see that ...
3/13 ≈ 0.230769... (6-digit repeating decimal)
The closest of the offered "reasonable estimate" fractions is 1/4 = 0.25.
__
Likewise, 6/11 ≈ 6/12 = 1/2. In decimal, these fractions are ...
6/11 = 0.54... (2-digit repeat)
1/2 = 0.5
__
We can also increase or decrease both numerator and denominator by the same amount to get a fraction with nearly the same value. This works best when the numbers are larger.
7/9 ≈ 6/8 = 3/4 . . . . . . both numerator and denominator decreased by 1
In decimal, these are ...
7/9 = 0.7... (1-digit repeat)
3/4 = 0.75
Answer:

Step-by-step explanation:
we are given the zeros and a point where it goes through of a quadratic equation
remember that when the roots are given then the function should be

where a is the leading coefficient and x1 and x2 are the roots
substitute:

simplify:

now the given point tells us that when x is 2 y is -14 therefore by using the point we can figure out a
substitute:

simplify parentheses:

simplify multiplication:

divide both sides by -7:

altogether substitute:

since it want the equation y should be

recall quadratic equation standard form:

so simplify parentheses:

distribute:

hence,
the equation of the parabola in standard form is <u>2</u><u>x</u><u>²</u><u>+</u><u>4</u><u>x</u><u>-</u><u>3</u><u>0</u><u>=</u><u>0</u>