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IceJOKER [234]
3 years ago
11

What is the reason for heat transfer from one substance to another?​

Chemistry
1 answer:
Musya8 [376]3 years ago
3 0

Answer:

Difference in temperature

Explanation:

According to thermodynamics, heat transfer occurs when heat from a high temperature reservoir moves to a low temperature reservoir. For heat to be transferred, the two objects should have different temperatures with one having more temperature than the other. Heat transfer in solids is by conduction, in fluids is by convection and by radiation.

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Which of the following leads to a higher rate of diffusion?
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I thought the answer is d

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3 years ago
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3 years ago
Why is it better to conduct an experiment more than once?
lilavasa [31]

The first reason to repeat experiments is simply to verify results. Different science disciplines have different criteria for determining what good results are. Biological assays, for example must be done in at least triplicate to generate acceptable data. Science is built on the assumption that published experimental protocols are repeatable.


2)      The next reason to repeat experiments is to develop skills necessary to extend established methods and develop new experiments. “Practice make perfect” is true for the concert hall and the chemical laboratory.


3)      Refining experimental observations is another reason to repeat. Maybe you did not follow the progress of the reaction like you should have.


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8 0
3 years ago
A 44.0 g sample of an unknown metal at 99.0 oC was placed in a constant-pressure calorimeter of negligible heat capacity contain
tatiyna

Answer:

C_m=0.474\frac{J}{g\°C}

Explanation:

Hello.

In this case, since this is a system in which the water is heated up and the metal is cooled down in a calorimeter which is not affected by the heat lose-gain process, we can infer that the heat lost by the metal is gained be water, it means that we can write:

Q_m=-Q_w

Thus, in terms of masses, specific heats and temperatures we can write:

m_mC_m(T_{eq}-T_m)=-m_wC_w(T_{eq}-T_w)

Whereas the equilibrium temperature is the given final temperature of 28.4 °C and we can compute the specific heat of the metal as shown below:

C_m=\frac{-m_wC_w(T_{eq}-T_w)}{m_m(T_{eq}-T_m)}

Plugging the values in and since the density of water is 1.00 g/mL so the mass is 80.0g, we obtain:

C_m=\frac{-80.0g*4.184\frac{J}{g\°C} (28.4\°C-24.0\°C)}{44.0g(28.4\°C-99.0\°C)}\\\\C_m=0.474\frac{J}{g\°C}

Best regards!

6 0
3 years ago
(03.03 LC)
scoundrel [369]
I believe the answer is option B. The bonded pair of valence electrons are shown using circles
8 0
3 years ago
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