Yes, free electrons appear in balanced redox reaction equations. However, this is only true for half-reactions. This is because redox reactions primarily involve the transfer of electrons, which are better visualized if explicitly shown in the balanced reactions. In reduction reactions, electrons are placed on the left side of the equation. Oxidation reactions show electrons on the right side of the equation.
Explanation:
A half reaction is either the chemical reaction or reduction reaction part of an oxidoreduction reaction. A half reaction is obtained by considering the amendment in chemical reaction states of individual substances concerned within the oxidoreduction reaction. Half-reactions are usually used as a way of leveling oxidoreduction reactions.The half-reaction on the anode, wherever chemical reaction happens, is Zn(s) = Zn2+ (aq) + (2e-).
The metal loses 2 electrons to create Zn2+. The half-reaction on the cathode wherever reduction happens is Cu2+ (aq) + 2e- = Cu(s).
Here, the copper ions gain electrons and become solid copper.
The molarity is calculated using the following rule:
molarity = number of moles of solvent / volume of solution (in liters)
We have the volume of solution = 250 ml = 0.25 liters and the molarity = 3 m
Substituting in the equation, we get:
3 = number of moles / 0.25
number of moles = 3 x 0.25 = 0.75 moles
Answer:
these elements do not have the same masses.
Answer:
no it is a ionic compound
Answer:
N2O(g) + 3 H2O(l) ---------------> 2 NH3(g) + 2 O2(g)
Explanation:
If we look at the reaction stated in the question, we will notice that the option chosen in the answer is the reverse of that reaction.
One thing is clear, if a reaction is possible, then its reverse reaction is equally possible. The equilibrium position may shift towards the forward or reverse reaction based on the conditions of the reaction.
Hence if the reaction, 2NH3(g) + 2O2(g) → N2O(g) + 3H2O(l) is possible, then the reaction, N2O(g) + 3 H2O(l) ---------------> 2 NH3(g) + 2 O2(g) is also possible.
