Answer: By understanding conversion factors and how they are related to each other
Explanation:
Dimensional Analysis is a step by step approach to solving problems in Physics, Chemistry , and Mathematics. It involves having a clear knowledge and understanding to be able to convert a given unit to another in the same dimension using conversion factors and knowing how they are related to each other.
For instance, In Chemistry, we want to Convert 120mL to L.(note that ml stands for millilitres and ;L stands for litres)
Or first approach will be to write out the conversion factor related to our problem which is
1000ml =1L
such that 120ml = (we cross multiply))
giving us 120ml x 1L/1000ml =0.12L
This same process is applied to convert any type of dimensional analysis problems be it physics or mathematics.
Answer:
15.2 g H2
Explanation:
2H2O -> 2H2 + O2
9.06 x 10^24 molecules x (1 mol/6.022 x 10^23 molecules) x (2 mol H2/2 mol H2O) x (1.008 g/1 mol) = 15.2 g H2
Answer:
The correct option is: Cost of materials used in manufacture
Explanation:
There are two types of costs of an object: the internal costs and the external costs.
The internal cost of an object is the direct monetized cost. It refers to the cost involved in the <u>production or manufacturing of a given objec</u>t. Example: labor, <u>material required</u>, equipment, energy, and overhead expenses.
The answer is B but iam not sure about the answer
Answer:
-1190.24 kJ
Explanation:
The enthalpy change in a chemical reaction that produces or consumes gases is given by the expression:
ΔH = ΔU + Δngas RT
where Δn gas is the change of moles of gas, R is the gas constant,and T is temperature.
Now from the given balanced chemical reaction, the change in number of mol gas is equal to:
Δn gas = mole gas products - mole gas reactants = 2 - 5/2 = -1/2 mol
Sionce we know ΔU and the temperature (298 K), we are in position to calculate the change in enthalpy.
ΔH = -1189 x 10³ J + (-0.5 mol ) 8.314 J/Kmol x 298 K
ΔH = -1.190 x 10⁶ J = -1.190 x 10⁶ J x 1 kJ/1000 J = -1.190 x 10³ J
