The system of standard automotive license plates allows for a variety of standard plates is 39917124 ways.
<h3>Define the term permutation?</h3>
- The number of potential arrangements for a given set is assessed mathematical terms, but this procedure is referred to as permutation.
- The arrangement's order is essential when using permutations.
For the stated data;
Standard car license plates in a nation typically have 3 digits, 2 letters, and 2 numbers.
There are total 9 digits (0 - 9).
There are total 26 letter (A - Z)
Repetitions of letters and numbers given allowed.
Thus, numbers and the letters ca be arranged as;
1st place = 9 ways.
2nd place = 9 ways.
3nd place = 9 ways.
4th place = 26 ways.
6th place = 26 ways.
7th place = 9 ways.
8th place = 9 ways.
Total ways = 9×9×9×26×26×9×9
Total ways = 39917124
Thus, the system of standard automotive license plates allows for a variety of standard plates is 39917124 ways.
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Answer:
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Step-by-step explanation:
First let's make the denominators equal, so that we can compare the two fractions more easily.
To do this, we have to find a number that both 15 and 9 divide into. The smallest number that this can happen to is 45.
15 x 3 = 45
9 x 5 = 45
So we have to multiply 15 by 3 in order to make it into 45. If we're changing the denominator, the numerator must change too, by the same multiplier.
4 ---> 4 x 3 = 12
--
15 ---> 15 x 3 = 45
4/15 = 12/45
5 ---> 5 x 5 = 25
--
9 ---> 9 x 5 = 45
5/9 = 25/45
To find how many times more rings there are, we divide 25 by 12. As the result of this isn't an integer, we leave the answer as a fraction:
There rings inventory is 25/12 times bigger than the earrings inventory.
Given:
A man owns 3/4 of the share of a business and sells 1/3 of his shares for Bir 10,000.
To find:
The value of the business in Bir.
Solution:
Let x be the value of the business.
It is given that a man owns 3/4 of the share of a business and sells 1/3 of his shares for Bir 10,000.
Multiply both sides by 4.
Therefore, the value of the business is 40,000 Bir.
Smaller the mosquitoes possibly fly only 9mph a car coming at 60 would destroy mosquito obviously the force of a moving object will move it
