HELP ME ASAPPP PLSSSSS

Two 10g blocks, one of copper and one of iron, were heated from 300 K to 400K (a temperature difference of 100 K).

vova2212 [387]

Energy absorbed by Iron block E (iron) = 460.5 J

Energy absorbed by Copper block E (Copper) = 376.8 J

<u>Explanation:</u>

To find the heat absorbed, we can use the formula as,

q = m c ΔT

Here, Mass = m = 10 g = 0.01 kg

ΔT = change in temperature = 400 - 300 = 100 K = 100 - 273 = -173 °C

c = specific heat capacity

c for iron = 460.5 J/kg K

c for copper = 376.8 J/kg K

Plugin the values in the above equation, we will get,

q (iron) = 0.01 kg × 460.5 J/kg K × 100 K

= 460.5 J

q (copper) = 0.01 kg × 376.8 J/kg K × 100 K

= 376.8 J

3 0

2 years ago

Calculate the pH of: (a) 0.1M HCl; (b) 0.1M NaOH; (c) 3 X 10% M HNO3; (d) 5 X 10-10 M HCIO.; and (e) 2 x 10-8 M KOH.

Shtirlitz [24]

Answer:

(a) $pH = -Log (0.1M) = 1$

(b) $pH = -Log (10^{-13}M) = 13$

(c) $pH = -Log (3x10^{-3}M) = 2.5$

(d) $pH = -Log (4.93x10^{-10}M) = 9.3$

(e) $pH = -Log (5^{-7}M) = 6.3$

Explanation:

To calculate de pH of an acid solution the formula is:

$pH = -Log ([H^{+}]) = 1$

were [H^{+}] is the concentration of protons of the solution. Therefore it is necessary to know the concentration of the protons for every solution in order to solve the problem.

(a) and (c) are strong acids so they dissociate completely in aqueous solution. Thus, the concentration of the acid is the same as the protons.

(b) and (e) are strong bases so they dissociate completely in aqueous solution too. Thus, the concentration of the base is the same as the oxydriles. But in this case it is necessary to consider the water autoionization to calculate the protons concentration:

$K_{w} =[H^{+} ][OH^{-}]=10^{-14}$

clearing the $[H^{+} ]$

$[H^{+} ]=\frac{10^{-14}}{[OH^{-}]}$

(d) is a weak base so it is necessary to solve the equilibrium first, knowing $Ka=3.24x10^{-8}$

The reaction is $HClO$ → $H^{+} + CO^{-}$ so the equilibrium is

$Ka=3.24x10^{-8}=\frac{x^{2}}{5x10^{-8}-x}$

clearing the <em>x</em>

${x^{2}={1.62x10^{-17}-3.24x10^{-8}x}$

$x=[H^{+}]=4.93x10^{-10}$

6 0

3 years ago

The final acceptor for hydrogen ions in aerobic cellular respiration is

Whitepunk [10]

The appropriate response is oxygen. Cellular respiration is the procedure cells use to make vitality. Cells in our body join glucose and oxygen to make ATP and carbon dioxide. Oxygen is utilized as an electron acceptor inside the electron transport tie of vigorous breath to create adenosine triphosphate or ATP. This compound is a fundamental part in intracellular vitality exchange.

5 0

2 years ago

Describe the spin of carbon-14's valence electrons and explain how you came about your answer.

Snezhnost [94]

we have to know the spin of valence electrons of carbon-14

There are four unpaired electron which are called as valence electron also.The spin of the four unpaired electron is either upfilled or down filled.

The ground state electronic configuration of C-atom is 1s²2s²2p² and one electron from 2s orbital gets excited to 2p orbital. The elctronic configuration in excited state is 1s²2s¹ $2p_{x}^{1} 2p_{y}^{1}2p_{z}^{1}$ .

The electron jumps because half-filled orbitals are more stable. Exchange energy is less than pairing energy.

8 0

2 years ago

) The atomic number of magnesium is 12.

Alisiya [41]

Answer: The difference between these 3 isotopes is the number of neutrons.

The atomic mass of an atom is the number of protons plus neutrons. We know that the atomic number of magnesium is 12, so therefore there are 12 protons.

In Magnesium-24, there are 24-12 neutrons = 12 neutrons.

In Magneusium-25, there are 25-12 neutrons = 13 neutrons

In Magnesium-26, there are 26-12 neutrons = 14 neutrons

4 0

2 years ago