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Sphinxa [80]
2 years ago
15

Please help!

Chemistry
1 answer:
Viktor [21]2 years ago
6 0

Answer:

3.141592653589793236   the numbers of pie.

Also yes her model correctly shows.

What could be correct about her model is that all substances are different properties of the stating substance and also all substances match.

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1) The hydrocarbon C15 H32 burns to form carbon dioxide and water. Write the equation for the reaction.
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8 0
2 years ago
Iridium has only two naturally occurring isotopes. Ir-191 with arelative mass of 190.96058 and Ir-193 with a relative mass of192
OLEGan [10]

<u>Answer:</u> The fractional abundance of Ir-191 is 0.372

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

Let the fractional abundance of Ir-191 be x and that of Ir-193 isotope be (1-x)

<u>For isotope 1 (Ir-191):</u>

Mass of isotope 1 = 190.96058 amu

Fractional abundance of Ir-191 = x

<u>For isotope 1 (Ir-193):</u>

Mass of isotope 1 = 192.96292 amu

Fractional abundance of Ir-193 = (1 - x)

Average atomic mass of iridium = 192.217 amu

Putting values in equation 1, we get:

192.217=[(190.96058\times x)+(192.96292\times (1-x))]\\\\x=0.372

Hence, the fractional abundance of Ir-191 is 0.372

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3 years ago
Which element family is all 2-
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Alkaline Earth Metals

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