Question

The reaction below shows how silver chloride can be synthesized. AgNO3 NaCl Right arrow. NaNO3 AgCl How many moles of silver chloride are produced from 15. 0 mol of silver nitrate? 1. 0 mol 15. 0 mol 30. 0 mol 45. 0 mol.

Answer 1

From 15 mol of Silver nitrate, the moles of silver chloride produced have been 15 mol. Thus, option B is correct.

The balanced chemical reaction for the synthesis of silver chloride has been:

$\rm AgNO_3\;+\;NaCl\;\rightarrow\;AgCl\;+\;NaNO_3$

From the balanced equation, since there has presence equal moles of silver nitrate and sodium chloride, the moles of silver chloride formed has been equivalent. Thus, 1 mole of silver nitrate gives 1 mole of silver chloride.

The moles of silver nitrate available are,  $\rm M_A_g_N_O_3=15\;mol$

The moles of silver nitrate produced can be given as:

$\rm 1\;mol\;AgNO_3=1\;mol\;AgCl\\15\;mol\;AgNO_3=15\;\times\;1\;mol\;AgCl\\15\;mol\;AgNO_3=15\;mol\;AgCl$

Thus, the moles of silver chloride produced have been 15 mol. Thus, option B is correct.

For more information about moles produced, refer to the link:

brainly.com/question/10606802

Answer 2

Answer:

15 mol

Explanation:

the balanced equation is AgNO3 + NaCl > NaNO3 + AgCl.

the stequiometry of the reactions says: one mol of silver nitrate reacts with one one mol of silver chloride to produce one mol of silver nitrate and one mol of sodium chloride.

by proportions, if you have 15 mol of AgNO3 you're gonna have 15 mol of AgCl