<h3>
Answer:</h3>
2000 atoms
<h3>
Explanation:</h3>
We are given the following;
Initial number of atoms of radium-226 as 8000 atoms
Time taken for the decay 3200 years
We are required to determine the number of atoms that will remain after 3200 years.
We need to know the half life of Radium
- Half life is the time taken by a radio active material to decay by half of its initial amount.
- Half life of Radium-226 is 1600 years
- Therefore, using the formula;
Remaining amount = Original amount × 0.5^n
where n is the number of half lives
n = 3200 years ÷ 1600 years
= 2
Therefore;
Remaining amount = 8000 atoms × 0.5^2
= 8000 × 0.25
= 2000 atoms
Thus, the number of radium-226 that will remain after 3200 years is 2000 atoms.
<span>(1) 5 because it it below 7 and anything below ph 7 is acidic! Hope this helps you!! =')</span>
Answer:
THE PRESSURE EXERTED BY THE GAS IS THEREFORE 2.88 atm.
Explanation:
Boyle's law states that at constant temperature, the volume of a given mass of gas is inversely proportional to the pressure of the gas.
Mathematically, P1 V1 = P2 V2
Write out the values of the variables given:
P1 = 2.4 atm
V1 = 1.8 L
V2 = 1.5 L
P2 = unknown
Re-arranging the variables by making P2 the subject of the equation, we have:
P2 = P1 V1 / V2
P2 = 2.4 * 1.8 / 1.5
P2 = 2.9=88 atm
Hence, the pressure exerted by the gas is therefore 2.88 atm
