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evablogger [386]
3 years ago
12

How does the strength of the force effect the velocity of the object?

Chemistry
1 answer:
Thepotemich [5.8K]3 years ago
4 0

Answer:

nertial mass is a measure of how difficult it is to change the velocity of an object. Example. Calculate the force needed to accelerate a 22 kg cheetah at 15 m/s².

Explanation:

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When zinc nitrate is heated, zinc oxide, nitrogen dioxide(NO2) and oxygen gas are
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Answer:

i) 16.5g of ZnO

ii) 9.8 dm³ of NO2

Explanation:

The working is shown in the photo so kindly refer to it

6 0
3 years ago
What is the theoretical yield of moles of hydrogen that can be produced from 0.032g of MG?
Ugo [173]

Answer:

1.31x10⁻³ moles of H₂

Explanation:

This is the equation:

Mg(s)  +   2H₂O (g)   →   Mg(OH)₂ (aq)   +    H₂(g)

Ratio is 1:1, so 1 mol of Mg is needed to produce 1 mol of H₂

Mass / Molar mass = Mol

0.032 g / 24.3 g/m = 1.31x10⁻³ moles

1.31x10⁻³ moles of H₂(g)

5 0
3 years ago
The balance reads 221.5 _________ and is measuring an object's _____________. grams; mass Newton's; mass kilograms; mass Newton'
azamat

Answer: grams;mass

Explanation: :)  I took the test.

5 0
2 years ago
The element silver exists in nature as two isotopes: 107Ag has a mass of 106.9051 u, and 109Ag has a mass of 108.9048 u. The ave
Lilit [14]

Answer:

107Ag has abundance of 51.7%

109Ag has abundance of 48.3%

Explanation: Please see attachment for explanation

3 0
3 years ago
In one sample of a compound of copper and oxygen, 3.12g of the compound contains 2.50g of copper and the remainder is oxygen. Ca
blsea [12.9K]

Answer:

% composition O = 19.9%

% composition Cu = 80.1%

Explanation:

Given data:

Total mass of compound = 3.12 g

Mass of copper = 2.50 g

Mass of oxygen = 3.12 - 2.50 = 0.62 g

% composition = ?

Solution:

Formula:

<em>% composition = ( mass of element/ total mass)×100</em>

% composition Cu = (2.50 g / 3.12 g)×100

% composition Cu = 0.80 ×100

% composition Cu = 80.1%

For oxygen:

<em>% composition = ( mass of element/ total mass)×100</em>

% composition O = (0.62 g / 3.12 g)×100

% composition O = 0.199 ×100

% composition O = 19.9%

5 0
3 years ago
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