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3 years ago

Solve for . Round to the nearest tenth, if necessary.

Mathematics

1 answer:

Len [333]3 years ago

7 0

Answer:

x ≈ 8.7

Step-by-step explanation:

Using the sine ratio in the right triangle

sin75° = $\frac{opposite}{hypotenuse}$ = $\frac{RS}{QS}$ = $\frac{x}{9}$ ( multiply both sides by 9 )

9 × sin75° = x , then

x ≈ 8.7 ( to the nearest tenth )

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Write 6600 as a product of its prime factors. (show your working out)

dem82 [27]

Answer: 2 × 3 × 5 × 11 = 330.

Step-by-step explanation: Since, the prime factors of 6600 are 2, 3, 5, 11. Therefore, the product of prime factors = 2 × 3 × 5 × 11 = 330.

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3 years ago

Factorise using the difference of two squares:<br> I)4x squared-(2x+3) squared

alex41 [277]

4x² - (2x + 3)²
4x² - (2x + 3)(2x + 3)
4x² - (2x(2x + 3) + 3(2x + 3))
4x² - (2x(2x) + 2x(3) + 3(2x) + 3(3))
4x² - (4x² + 6x + 6x + 9)
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8 0

3 years ago

The amount of money in a savings account after t years is represented by the function f(t)=3600(1.035)t .

timama [110]

Answer: The initial amount in the account = $3600

Step-by-step explanation:

Since we have given that

The amount of money in a savings account after t years is represented by the function

$f(t)=3600(1.035)^t$

As we know the formula "Compound Interest" :

$Amount=P(1+\frac{r}{100})^t\\\\Here,\\\\\text{ P denotes principal}\\\\\text{ R denotes Rate of interest}\\\\\text{ T denotes time}$

So, According to our question,

Rate of interest = 0.35 = 35%

So, equate the both the equations , we get that

Hence, The initial amount in the account = $3600

5 0

3 years ago

Read 2 more answers

SHow the process to solving (11-3) to the power of 2 times (-12) divided by 4<br> Pls dont scam

Grace [21]

Answer:

-192

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

What is 3/2m-m=4+1/2m

Annette [7]

Answer:

answer is 08

Step-by-step explanation:

3/2m-m=4+1/2*m

3m/2-m=4+1/2*m

3m/2-m=4+1/2m

3m/2-m=4+1m/2

3m/2-m=4+m/2

2(3m/2-m)=2(4+m/2)

m=m+8

5 0

3 years ago

Solve for . Round to the nearest tenth, if necessary.​

Solve for . Round to the nearest tenth, if necessary.