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olasank [31]
2 years ago
15

Solve for . Round to the nearest tenth, if necessary.​

Mathematics
1 answer:
Len [333]2 years ago
7 0

Answer:

x ≈ 8.7

Step-by-step explanation:

Using the sine ratio in the right triangle

sin75° = \frac{opposite}{hypotenuse} = \frac{RS}{QS} = \frac{x}{9} ( multiply both sides by 9 )

9 × sin75° = x , then

x ≈ 8.7 ( to the nearest tenth )

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Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

8 0
2 years ago
Simplify the polynomial (4n2 + 3n - 5) - (2n2 + 3n+ 6)
saul85 [17]

Answer:

2n^2 - 11

steep by steep explanation

=(4n^2 + 3n -5) -(2n^2 + 3n +6)

= 4n^2 +3n -5 - 2n^2 - 3n -6

= 2n^ - 11

3 0
3 years ago
Read 2 more answers
Evaluate 2n + t2 when n =-4 and t = -10
Tamiku [17]

Answer:

92

Step-by-step explanation:

Given

2n + t² ← substitute n = - 4 and t = - 10 into the expression

= 2(- 4) + (- 10)² = - 8 + 100 = 92

8 0
3 years ago
Read 2 more answers
PLSSSSS HELP I HAVE BEEN STUCK ON THIS FOR THE PAST HOUR!!!!!!!!!!!!!!!!!!!!!!!!!
vladimir1956 [14]

Answer:

- 6 \sqrt{2}

Step-by-step explanation:

simplify

\sqrt{28800}

to

120 \sqrt{2}

then

-0.05 × 120 = -6

then we have our answer

-6√2

6 0
3 years ago
In the diagram, which two angles are corresponding angles with angle 12?
Rama09 [41]

Answer:

It's 8 the answer is 8

Step-by-step explanation:

6 0
3 years ago
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