An 80g sample of 3 1 H decays, leaving 2.5g of 3 1 H.

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Serga [27]

Answer:

polymerization reaction

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3 years ago

miskamm [114]

Answer : The number of moles present in ammonia is, 70.459 moles.

Solution : Given,

Mass of ammonia = $1.2\times 10^3g$

Molar mass of ammonia = 17.031 g/mole

Formula used :

$\text{Moles of }NH_3=\frac{\text{ given mass of }NH_3}{\text{ molar mass of }NH_3}$

$\text{Moles of }NH_3=\frac{1.2\times 10^3g}{17.031g/mole}=70.459moles$

Therefore, the number of moles present in ammonia is, 70.459 moles.

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WITCHER [35]

I hope it helps you ❤️❤️❤️❤️

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Elodia [21]

(Left) I’m pretty sure

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iVinArrow [24]

10 grams of cocaine helps chalk to grow and the mass was increase a way lot more

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