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Molodets [167]
3 years ago
10

How do you use distributive property to solve 3,649 x 7

Mathematics
2 answers:
Rufina [12.5K]3 years ago
6 0

Answer:

Value of 3649×7 is:

25543

Step-by-step explanation:

We have to use the distributive property to solve 3649×7

3649 could also be written as

3649= 3000+600+40+9

3649×7= (3000+600+40+9)×7

            = 3000×7 + 600×7 + 40×7 + 9×7   (by using distributive property)

            = 21000+4200+280+63

            = 25543

Hence, Value of 3649×7 is:

25543

Tanzania [10]3 years ago
3 0
You distribute. First 3,000* 7.Then 600 *7. Then 40*7. Then 9 AM. Add it up Hopefully this helps
Tbh I forgot :)


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Answer:

(0,2)

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F(x)=x^3+3
lawyer [7]

Answer:

  (a)   -3/4

  (b)  -0.75

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Step-by-step explanation:

It's a bit hard to tell what constitutes an "iteration" when using the bisection method to approximate a polynomial root. For the purpose here, we'll say one iteration consists of ...

  • evaluating the function at the midpoint of the bracketing interval
  • choosing a smaller bracketing interval
  • identifying the x-value known to be closest to the solution

Thus, the result of the iteration consists of a bracketing interval and the choice of one of the interval's ends as the solution approximation.

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(a) We observe that the graphs intersect in the interval (-1, 0). For the first iteration, we evaluate f(x)-g(x) at x=-1/2. This tells us the solution is in the interval (-1, -1/2). The x-value closest to the root is x=-1/2.

For the second iteration, we evaluate the function f(x)-g(x) at x=-3/4. This tells us the solution is in the interval (-1, -3/4). The x-value closest to the root is x=-3/4.

For the third iteration, we evaluate the function f(x)-g(x) at x=-7/8. This tells us the solution is in the interval (-7/8, -3/4). The x-value closest to the root is x=-3/4.

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(b) The graph tells us the solution is approximately 0.7549. Rounded to 2 decimal places, the solution is approximately 0.75.

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(c) The above solution found after 3 iterations rounded to 2 decimal places is exactly 0.75.

__

See the attached table for function values.

_____

<em>Comment on bisection iteration</em>

Since you cut the interval containing the root in half with each iteration, you gain approximately one decimal place for each 3 iterations. When the function value is very nearly zero at one of the interval endpoints, it can take many more iterations to achieve a better result.

Here, it takes 4 more iterations before an x-value becomes closer to the solution (x≈-97/128). And it takes one more iteration to move the end of the interval away from -3/4. After these 5 more iterations (8 total), the solution is known to lie in the interval (-97/128, -193/256). The corresponding solution approximation is -193/256. It is still only correct to 2 decimal places.

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Ivenika [448]

The value of the expression, 5x^2 - 4, when x = 2 is: 16.

<h3>What is the the Value of an Expression?</h3>

To find the value of an expression, plug in the given value of the variable and solve by simplifying.

Given the expression, 5x^2 - 4, when x = 2, we would have:

5(2)^2 - 4

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Therefore, the value of the expression, 5x^2 - 4, when x = 2 is: 16.

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