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saw5 [17]
3 years ago
11

22

Chemistry
1 answer:
uranmaximum [27]3 years ago
8 0

Answer:

Oxygen atoms form two double bonds in silicon(IV) oxide.

Silicon(IV) oxide has a high melting point.

Explanation:

Silicon dioxide is structurally analogous to carbon dioxide in the sense that it also contains two oxygen atoms that are double bonded to silicon the central atom in the molecule.

Silicon dioxide has a very high melting point of about 1710 degrees centigrade because of its large macromolecular structure which requires much energy to break such intermolecular interactions.

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After James Chadwick discovered the neutron, atomic theory expanded to include isotopes. Isotopes have many practical uses. For
andrew-mc [135]

Answer:

The answer is C which is 8 neutrons

Explanation:

This is because all carbon isotopes have 6 protons in their nucleus. Carbon 14 have 2 extra neutron aside from only having 6. So 6 protons + 6 neutrons + 2 more extra makes 14 which makes it Carbon - 14. I hope this makes sense.

8 0
3 years ago
PLEASE HELP WILL MARK BRAINLEST!!!!
puteri [66]

Answer: c????????

Explanation:

6 0
3 years ago
If an atom has 8 protons and 8 neutrons in its nucleus, and 8 orbiting electrons, its atomic number would be
xxTIMURxx [149]
The atomic number is 8
Atomic number=number of proton or number of electrons
8 0
4 years ago
Identify the number and kinds of atoms present in a molecule of each compound. caffeine c8h10n4o2 iron iii sulfate fe2(so4)3
finlep [7]
This problem is very easy to answer. You simply have to look at the subscripts of each element of the compound.

1. For caffeine, which has a molecular formula of C₈H₁₀N₄O₂, it contains 8 atoms of Carbon, 10 atoms of Hydrogen, 4 atoms of Nitrogen and 2 atoms of Oxygen.

2. For Iron(III) Sulfate, which has a molecular formula of Fe₂(SO₄)₃, it contains 2 atoms of Iron, 3 atoms of Sulfur, and 12 atoms of Oxygen.
6 0
4 years ago
The enthalpy change for converting 1.00 mol of ice at -50.0 ∘c to water at 60.0∘c is ________ kj. the specific heats of ice, wat
guajiro [1.7K]
First, we have to get:

1- The heat required to increase T of ice from -50 to 0 °C:

according to q formula:

q1 = m*C*ΔT

when m is the mass of ice = mol * molar mass

                                             =  1 mol * 18 mol/g

                                            = 18 g

and C is the specific heat capacity of ice = 2.09 J/g-K

and ΔT change in temperature = 0- (-50) = 50°C

by substitution:

∴q1 = 18 g * 2.09 J/g-K *50°C

       = 1881 J = 1.881 KJ

2- the heat required to melt this mass of ice is :

q2 = n*ΔHfus 

when n is the number of moles of ice = 1 mol

and ΔHfus = 6.01 KJ/mol

by substitution:

q2 = 1 mol * 6.01 KJ/mol

     = 6.01 KJ

3- the heat required to increase the water temperature from 0°C to 60 °C is:

q3 = m*C*ΔT

when m is the mass of water = 18 g 

C is the specific heat capacity of water = 4.18 J/g-K

ΔT is the change of Temperature of water = 60°C - 0°C = 60°C

by substitution:

∴q3 = 18 g * 4.18 J/g-K * 60°C

      = 4514 J = 4.514 KJ

∴the total change of enthalpy = q1+q2+q3

                                                  = 1.881 KJ  +6.01 KJ + 4.514 KJ

                                                  = 12.405 KJ


5 0
4 years ago
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