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prisoha [69]
3 years ago
12

10. What is the atmospheric pressure if the partial pressures of nitrogen, oxygen, and

Chemistry
1 answer:
sashaice [31]3 years ago
7 0

Answer:

1.009 atm is the total pressure for the mixture

Explanation:

To determine the total pressure in atm, of the three gases (N₂, O₂ and Ar) we have to sum all the values.

Sum of partial pressures in a mixture = Total pressure

First of all, we need to convert the values from mmHg to atm

604.5 mmHg . 1atm / 760 mmHg = 0.795 atm

162.8 mmHg . 1atm / 760 mmHg = 0.213 atm

0.500 mmHg . 1atm / 760 mmHg = 6.58×10⁻⁴ atm

Partial pressure N₂ + Partial pressure O₂ + Partial pressure Ar = Total P

0.795 atm + 0.213 atm + 6.58×10⁻⁴ atm = 1.009 atm

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Answer:

The correct answer is a

Explanation:

The formula for density is mass ÷ volume. Hence, a balance is required to determine the mass while a measuring/graduated cylinder is required to determine the volume.

The ideal measuring cylinder and balance to be used should have an uncertainty of just 0.1 ml and 0.1 g respectively. This reduces the chances of the answer gotten from the formula above to be more than 3 significant figures.

For example, if the volume to be used is 4.0 ml and the mass of this volume is 3.5 g, the density will be

Density = 3.5 ÷ 4

Density = 0.875 g/cm³ or 0.875 g/ml

NOTE that cm³ is the same measurement as mL

The answer above is in 3 significant figures

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3 years ago
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CAESIUM is the most reactive metal............
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Use the half-reaction method to balance the following equation in acidic solution. It is not necessary to include any phases of
yawa3891 [41]

Answer:

2H⁺ + 2MnO4⁻ + 3CN⁻ → 2MnO₂  + H₂O + 3CNO⁻

Explanation:

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In right side permangante, with Mn element has +7 as oxidation number.

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This is the half reaction of reduction, where the Mn has gained 3 electrons.

in right side, cianide with C element has +2 as oxidation number. In the anion cianate, C acts with +4.

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( 4H⁺ + MnO4⁻ + 3e⁻  → MnO₂  + 2H₂O ) .2

(H₂O  +  CN⁻  →  CNO⁻  + 2e⁻  + 2H⁺) .3

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The electrons are now cancelled, and I can also modify water. In reactant side I have 3H₂O and in product side, I have 4H₂O so, H₂O in right side is gone so I finally obtained 1 H₂O on left. I had 8H⁺ on right, and 6H⁺ on left, so finally I obtained 2H⁺ on right, and the protons of product side are gone.

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C2h6o how many moles of ethanol are present in a 10.0 g sample of ethanol
Dmitriy789 [7]
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5 0
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a) synthesis- or combination- reaction

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