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Klio2033 [76]
3 years ago
8

Scientists have speculated that element 126 might have a moderate stability, allowing it to be synthesized and characterized. pr

edict what the condensed electron configuration of this element might be.
Chemistry
2 answers:
SIZIF [17.4K]3 years ago
5 0
The condensed electron configuration of this element might be is 8s^25g^6. The electronic configuration is a depiction of the distributions of different or various physical elements such as atoms, molecules, and also the electrons. The electronic configuration is said to be like a code that explains the relationships of electrons.
kirill115 [55]3 years ago
5 0

Answer:

5g2 6f2 7d1 8s2 8p1

Explanation:

The full electrons configuration for this element would be:

1s2 2s2 2p6   3s2 3p6 3d10   4s2 4p6 4d10 4f14   5s2 5p6 5d10 5f14 5g2    6s2 6p6 6d10 6f2    7s2 7p6 7d1   8s2 8p1

This configuration explains the electron orbit levels and the arrangement of all the electrons for that element. Each element has its own electron configuration. The configuration shown for element-126 is only a prediction, as the element is not naturally occurring on the planet.

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Explain ways that organisms interact in helpful and harmful ways.
I am Lyosha [343]
Organisms are living things. Us humans are also living things, so we are helpful and harmful to other organisms. For example: we can help another human being with something, or we can help a plant/tree grow if we water it. In return, they also help us by providing us with oxygen. however, we can also be harmful to each other and the environment, for example: we can't hurt each other, or plant or animals by killing them or we can hurt insects by stepping on them. Therefore, organisms are helpful and harmful to each other.
4 0
3 years ago
2) A container has an unknown quantity of gas at a pressure of 61.6 kPa, a volume of 3.9 liters, and a temperature
balu736 [363]

Answer:

3

Explanation:

5 0
3 years ago
What is the value for ∆Soreaction for the following reaction, given the standard entropy values? 2H2S(g) + SO2(g) 3Srhombic(s) +
Mademuasel [1]

Answer: \Delta S^{0} for the reaction is -186.75 J/K

Explanation:

Change in entropy (\Delta S^{0}) for the given reaction under standard condition is given by-

\Delta S^{0}= [3\times S_{rhombic}^{0}_{(s)}]+[2\times S_{H_{2}O}^{0}_{(g)}]-[2\times S_{H_{2}S}^{0}_{(g)}]-[1\times S_{SO_{2}}^{0}_{(g)}]

So \Delta S^{0} = [3\times 31.8 J/K.mol]+[2\times 188.825 J/K.mol]-[2\times 205.79 J/K.mol]-[1\times 248.22 J/K.mol] = -186.75 J/K

5 0
3 years ago
Be sure to answer all parts. For the complete redox reactions given here, write the half-reactions and identify the oxidizing an
OlgaM077 [116]

Answer : O_2 is the oxidizing agent and Fe is the reducing agent.

Explanation :

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The balanced redox reaction is :

4Fe+3O_2\rightarrow 2Fe_2O_3

The half oxidation-reduction reactions are:

Oxidation reaction : Fe\rightarrow Fe^{3+}+3e^-

Reduction reaction : O_2+4e^-\rightarrow 2O^{2-}

In order to balance the electrons, we multiply the oxidation reaction by 4 and reduction reaction by 3 then added both equation, we get the balanced redox reaction.

Oxidation reaction : 4Fe\rightarrow 4Fe^{3+}+12e^-

Reduction reaction : 3O_2+12e^-\rightarrow 6O^{2-}

4Fe+3O_2\rightarrow 2Fe_2O_3

In this reaction, 'Fe' is the reducing agent that loses an electron to another chemical species in a redox chemical reaction and itself gets oxidized and 'O_2' is the oxidizing agent that gain an electron to another chemical species in a redox chemical reaction and itself gets reduced.

Thus, O_2 is the oxidizing agent and Fe is the reducing agent.

7 0
3 years ago
In the world of chemistry, a 'mole' is a number of something... a very large number of something.
kipiarov [429]

Given:

No of atoms present= 8.022 x 10^23 atoms

Now we know that 1 mole= 6.022 x 10^23 atoms


Hence number of moles present in 8.022 x 10^23 atoms is calculated as below.

Number of moles

= 8.022 x 10^23/6.022x 10^23

=1.3 moles.

Hence we have 1.3 moles present.

3 0
3 years ago
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