<span>NaCl
First calculate the molar mass of NaCl and AgNO3 by looking up the atomic weights of each element used in either compound
Sodium = 22.989769
Chlorine = 35.453
Silver = 107.8682
Nitrogen = 14.0067
Oxygen = 15.999
Now multiply the atomic weight of each element by the number of times that element is in each compound and sum the results
For NaCl
22.989769 + 35.453 = 58.44277
For AgNO3
107.8682 + 14.0067 + 3 * 15.999 = 169.8719
Now calculate how many moles of each substance by dividing the total mass by the molar mass
For NaCl
4.00 g / 58.44277 g/mol = 0.068443 mol
For AgNO3
10.00 g / 169.8719 g/mol = 0.058868
Looking at the balanced equation for the reaction, there is a 1 to 1 ratio in molecules for the reaction. Since there is a smaller number of moles of AgNO3 than there is of NaCl, that means that there will be some NaCl unreacted, so the excess reactant is NaCl</span>
Answer:
Methane is a covalent bond. Methane is a chemical compound from the bonding one carbon atom and for hydrogen atoms. Although electronegativity increases as you go right of the periodic table, hydrogen has an electronegativity of 2.20. Chlorine has an electronegativity of 2.55. There difference in electron negativity (0.34). Therefore it is a non polar compound. If there difference was much greater, than they would form a ionic bond. Alkali metals tend to form the most ionic bond, but although hyrdogen is placed with them, it has a higher electronegativity so hydrogen is an exception.
Carbon has 4 valence electrons so it will want to gain 4 more electrons to become stable (Octet rule). Hydrogen has 1 valence electron, so it will want to lose it to become stable. Therefore, one carbon atom takes 1 electrons from 4 hydrogen atoms.
Answer:
600g for st product 477.5g for nd product
Elemento químico, símbolo Ag, número atómico 47 y masa atómica 107.870. Es un metal lustroso de color blanco-grisáceo. La plata, que posee las más altas conductividades térmica y eléctrica de todos los metales, se utiliza en puntos de contacto eléctricos y electrónicos.