Question

How many moles of Na₂CO₃ required to create 9.54 liters of a 3.4 M solution

Answer 1

Answer: 32.4 moles Na2CO3

Explanation: Molarity is moles of solute per unit Liter of solution

M= n/L

To solve for moles (n) we derive the equation:

n = M x L

= 3.4 M x 9.54 L

= 32.4 moles Na2CO3

Answer 2

Answer:

The answer to your question is 32.44 moles

Explanation:

Data

moles of Na₂CO₃ = ?

volume = 9.54 l

concentration = 3.4 M

Formula

Molarity = $\frac{number of moles}{volume}$

Solve for number of moles

number of moles = Molarity x volume

Substitution

Number of moles = (3.4)( 9.54)

Simplification

Number of moles = 32.44