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postnew [5]
3 years ago
11

How many moles of Na₂CO₃ required to create 9.54 liters of a 3.4 M solution

Chemistry
2 answers:
Lynna [10]3 years ago
4 0

Answer: 32.4 moles Na2CO3

Explanation: Molarity is moles of solute per unit Liter of solution

M= n/L

To solve for moles (n) we derive the equation:

n = M x L

= 3.4 M x 9.54 L

= 32.4 moles Na2CO3

GarryVolchara [31]3 years ago
3 0

Answer:

The answer to your question is 32.44 moles

Explanation:

Data

moles of Na₂CO₃ = ?

volume = 9.54 l

concentration = 3.4 M

Formula

Molarity = \frac{number of moles}{volume}

Solve for number of moles

number of moles = Molarity x volume

Substitution

Number of moles = (3.4)( 9.54)

Simplification

Number of moles = 32.44

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The same heat transfer into identical masses of different substances produces different temperature changes. Calculate the final
myrzilka [38]

Answer: final temperatures will be

a) water 21 C

b) concrete  20.005 C

c) steel   20.008 C

d) mercury  53 C

Explanation:

Change in temp dT = dH / (mass x specific heat)

Specific heat of these materials can be found from many sources:

water = 1 kcal / kg C

concrete = 210 kcal / kg C

steel = 114 kcal / kg C

mercury = 0.03 kcal /kg C

So dT (water) from 1 kcal heat into 1 kg water = 1 kcal / (1 kg x 1 kcal/kg C) = 1 C therefore the final temperature is 20 + 1 = 21 C

But dT (steel) = 1 kcal / (1kg x 114 kcal/kg C) = 0.008 C so the final temperature is 20 + 0.008 = 20.008 C

The results for concrete and mercury are calculated in the same way

7 0
2 years ago
Please help! How many grams is 4.5 x 10^27
Eva8 [605]

Answer: The answer is 4.5e+27 grams, I hope I helped!

Explanation: N/A (I threw away my paper ^^")

4 0
3 years ago
For each pair below, select the sample that contains the largest number of moles. Pair A 2.50 g O2 2.50 g N2
raketka [301]

Answer:

Explanation:

Pair  2.50g of O₂ and 2.50g of  N₂

The atoms sample with the largest number of moles since the masses are the same would be the one with lowest molar mass according the the equation below:

Number of moles = \frac{mass }{molarmass}

Atomic mass of O = 16g and N = 14g

Molar mass of O₂ = 16 x 2 = 32gmol⁻¹

Molar mass of N₂ = 14 x 2 = 28gmol⁻¹

Number of moles of O₂ = \frac{2.5}{32} = 0.078mole

Number of moles of N₂ = \frac{2.5}{28} =  0.089mole

We see that N₂ has the largest number of moles

4 0
3 years ago
Read 2 more answers
What effect do antibiotics have on bacteria?
STALIN [3.7K]

Answer:

Antibiotics destroy bacteria

8 0
3 years ago
The antibiotic doxycycline is used to treat Lyme disease. A 100 mg dose of the antibiotic consists of 59.5 mg of C, 5.40 mg of H
never [62]

Answer:

C₁₁H₁₂NO₄

Explanation:

In order to determine the empirical formula of doxycycline, we need to follow a series of steps.

Step 1: Determine the centesimal composition

C: 59.5 mg/100 mg × 100% = 59.5%

H: 5.40 mg/100 mg × 100% = 5.40%

N: 6.30 mg/100 mg × 100% = 6.30%

O: 28.8 mg/100 mg × 100% = 28.8%

Step 2: Divide each percentage by the atomic mass of the element

C: 59.5 /12.0 = 4.96

H: 5.40/1.00 = 5.40

N: 6.30/14.0 = 0.450

O: 28.8/16.0 = 1.80

Step 3: Divide all the numbers by the smallest one

C: 4.96/0.450 = 11

H: 5.40/0.450 = 12

N: 0.450/0.450 = 1

O: 1.80/0.450 = 4

The empirical formula of doxycycline is C₁₁H₁₂NO₄

5 0
3 years ago
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