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2 years ago

How many moles of Na₂CO₃ required to create 9.54 liters of a 3.4 M solution

Chemistry

2 answers:

Lynna [10]2 years ago

4 0

Answer: 32.4 moles Na2CO3

Explanation: Molarity is moles of solute per unit Liter of solution

M= n/L

To solve for moles (n) we derive the equation:

n = M x L

= 3.4 M x 9.54 L

= 32.4 moles Na2CO3

GarryVolchara [31]2 years ago

3 0

Answer:

The answer to your question is 32.44 moles

Explanation:

Data

moles of Na₂CO₃ = ?

volume = 9.54 l

concentration = 3.4 M

Formula

Molarity = $\frac{number of moles}{volume}$

Solve for number of moles

number of moles = Molarity x volume

Substitution

Number of moles = (3.4)( 9.54)

Simplification

Number of moles = 32.44

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The question is incomplete. Her eis the complete question.

Steam reforming methane (CH4) produces "synthesis gas", a mixture of carbon monoxide gas and hydrogen gas, which is the starting point for many important industrial chemical syntheses. An industrial chemist studying this reaction fills a 125L tank with 20 mol of methane gas and 10 mol of water vapor at 38°C. He then raises the temperature, and when the mixture has come to equilibrium measures the amount of gas hydrogen to be 18 mol. Calculate the concentration equilibrium constant for the steam reforming of methane at the final temperature of the mixture. Round your answer to significant digits.

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Molarity of H20:

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Molarity of H2:

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The equilibrium constant is given by:

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