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postnew [5]
3 years ago
11

How many moles of Na₂CO₃ required to create 9.54 liters of a 3.4 M solution

Chemistry
2 answers:
Lynna [10]3 years ago
4 0

Answer: 32.4 moles Na2CO3

Explanation: Molarity is moles of solute per unit Liter of solution

M= n/L

To solve for moles (n) we derive the equation:

n = M x L

= 3.4 M x 9.54 L

= 32.4 moles Na2CO3

GarryVolchara [31]3 years ago
3 0

Answer:

The answer to your question is 32.44 moles

Explanation:

Data

moles of Na₂CO₃ = ?

volume = 9.54 l

concentration = 3.4 M

Formula

Molarity = \frac{number of moles}{volume}

Solve for number of moles

number of moles = Molarity x volume

Substitution

Number of moles = (3.4)( 9.54)

Simplification

Number of moles = 32.44

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<h3>Mole-mass relationships:</h3>

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Learn more about mole-mass relationships: brainly.com/question/18311376

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