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Andrews [41]
3 years ago
11

Can anybody help with this GCSE physics question?

Physics
1 answer:
Serjik [45]3 years ago
8 0

Answer:

volume = 18.45 \times 18.45  \times 18.45 \\  = 0.00000628 \:  {m}^{3}  \\ mass = density \times volume \\  = 8.0 \times  {10}^{3}  \times 0.00000628 \\  = 0.05\: kg

\small  \boxed{ \boxed { becker}}

<u>〰</u><u>〽</u>

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A reaction taking place in a container with a piston-cylinder assembly absorbs 4850. J of heat and has a change in the internal
Maslowich

Answer:

V_f = 16.3 Ltr

Explanation:

As per first law of thermodynamics we know that

heat absorbed = change in internal energy + Work done

so we have

Heat = 4850 J

\Delta U = 1618.5 J

so work done is given as

4850 = 1618.5 + W

W = 3231.5 J

now we know that at constant pressure the work done is given as

W = P\Delta V

3231.5 = P(V_f - V_i)

3231.5 = 5.5 \times 1.01 \times 10^5(V_f - 10.5 \times 10^{-3})

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or we have

V_f = 16.3 Ltr

6 0
3 years ago
A 5 kg
kotykmax [81]

Answer:

<em>The object-Earth system is open</em>

F_n=ma=5\ (7.2)=36\ N

Explanation:

<u>Accelerated Motion </u>

When an object is released in free air (with no other forces than the gravity), it describes a free-fall motion and the formulas include the acceleration of gravity as part of the calculations. But when there is another external force, then the acceleration is not the gravity, but the result of the net force exerted on the mass of the object.

By definition, an open system includes the exchange of energy from and to the surroundings, that is why all systems surrounding our planet are considered as open systems. In our case, the object is interacting with the planet's gravity and there is some other external force, which will be computed later. The object-Earth system is open.

If the object starts from rest, its initial speed is zero, and

v_f=a\ t

where a is the acceleration and t is the time. The distance traveled is given by :

\displaystyle y=\frac{a\ t^2}{2}

From the two above equations, we find that:

v_f^2=2ay

Solving for a

\displaystyle a=\frac{v_f^2}{2y}

\displaystyle a=\frac{12^2}{2\ (10)}

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It means the net force is

F_n=ma=5\ (7.2)=36\ N

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W=5\ (9.8)=49 N

This means there is some external force acting upwards delaying the object's fall of a magnitude of

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3 0
3 years ago
A circular flat coil that has N turns, encloses an area A, and carries a current i, has its central axis parallel to a uniform m
Aneli [31]

Answer:

A. Zero

Explanation:

The force on a coil of N turns, enclosing an area, A and carrying a current I in the presence of a magnetic field B, is :

F = N * I * A * B * sinθ

Where θ is the angle between the normal of the enclosed area and the magnetic field.

Since the normal of the area is parallel to the magnetic field, θ = 0

Hence:

F = NIABsin0

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4 0
3 years ago
A 10cm tall object is placed perpendicular to
wlad13 [49]

My answer is in the picture

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4 0
3 years ago
A diver is on a board 1.80 m above
Virty [35]

Answer:

v = 6.95 m/s

Explanation:

Given that,

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The initial speed of the diver, u = 3.62 m/s

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So, she will hit the water with a speed of 6.95 m/s.

8 0
3 years ago
Read 2 more answers
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