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alekssr [168]
3 years ago
13

A virtual image produced by a lens is always

Physics
2 answers:
JulijaS [17]3 years ago
5 0
The Answer Is D Because When Uu Magnify Large Items The Image Is Reflected Back To The Magnifying Glass Which Makes The Image Appear In The Back
Dmitry_Shevchenko [17]3 years ago
3 0

<em><u>Option (D) is correct. The virtual image is always firmed in front of the lens or on the same side of the lens as of the object.</u></em>

Explanation:

The image formed by the lens are categorized in two broad categories.

  • Real Images
  • Virtual Images

The Real Image is a image that is formed by the actual meeting of the incoming rays from the object. The real image is an image that can be obtained on the screen.

The Virtual Image is an image that is formed by the the imaginary meeting of the incoming rays from the object. The virtual image cannot be obtained on the screen.

Since the real image is formed by the actual meeting of the rays, the rays would meet on the other side of the lens as that of the object. It means that a real image is formed behind the lens whereas for a virtual image, the diverging rays from object are extended in backward direction and made to meet on the same size as that of the object.

Thus, <em><u>Option (D) is correct. The virtual image is always firmed in front of the lens or on the same side of the lens as of the object.</u></em>

<em><u></u></em>

Learn More:

1. Nature of the image formed by the mirror brainly.com/question/11743071

2. What type of mirror do dentist use brainly.com/question/997618

3. A small bulb has a resistance of 2 ohm when cold brainly.com/question/10421964

Answer Details:

Grade: Middle School

Subject: Physics

Chapter: Lens

Keywords:

virtual, image, real, object, rays, incoming, converging, diverging, lens, back of lens, front, smaller, larger, screen, obtained.

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wel

The question is incomplete! The complete question along with answer and explanation is provided below.

Question:

A 0.5 kg mass moves 40 centimeters up the incline shown in the figure below. The vertical height of the incline is 7 centimeters.

What is the change in the potential energy (in Joules) of the mass as it goes up the incline?  

If a force of 1.0 N pulled up and parallel to the surface of the incline is required to raise the mass back to the top of the incline, how much work is done by that force?

Given Information:  

Mass = m = 0.5 kg

Horizontal distance = d = 40 cm = 0.4 m

Vertical distance = h = 7 cm = 0.07 m

Normal force = Fn = 1 N

Required Information:  

Potential energy = PE = ?

Work done = W = ?

Answer:

Potential energy = 0.343 Joules

Work done = 0.39 N.m

Explanation:

The potential energy is given by

PE = mgh

where m is the mass of the object, h is the vertical distance and g is the gravitational acceleration.

PE = 0.5*9.8*0.07

PE = 0.343 Joules

As you can see in the attached image

sinθ = opposite/hypotenuse

sinθ = 0.07/0.4

θ = sin⁻¹(0.07/0.4)

θ = 10.078°

The horizontal component of the normal force is given by

Fx = Fncos(θ)

Fx = 1*cos(10.078)

Fx = 0.984 N

Work done is given by

W = Fxd

where d is the horizontal distance

W = 0.984*0.4

W = 0.39 N.m

3 0
2 years ago
What are the functions of the female reproductive system?
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Near the surface of Earth an electric field points radially downward and has a magnitude of approximately 100 N/C. What charge (
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Answer:

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Sign-Negative

Explanation:

We are given that

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Mass of charge=3 g=3\times 10^{-3}kg

1kg=1000g

We have to find the magnitude and sign of  charge would have to be placed on a penny .

By newton's second law

\sum F_y=ma

\sum F_y=qE-mg

Substitute the values then we get

qE-mg=ma

Substitute the values then we get

q(100)-3\times 10^{-3}(9.8)=3\times 10^{-3}(0.19)

100q-29.4\times 10^{-3}=0.57\times 10^{-3}

100q=0.57\times 10^{-3}+29.4\times 10^{-3}=29.97\times 10^{-3}

q=\frac{29.97\times 10^{-3}}{100}

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poizon [28]

Answer:

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