Answer:

Explanation:
Hello.
In this case, since this is a system in which the water is heated up and the metal is cooled down in a calorimeter which is not affected by the heat lose-gain process, we can infer that the heat lost by the metal is gained be water, it means that we can write:

Thus, in terms of masses, specific heats and temperatures we can write:

Whereas the equilibrium temperature is the given final temperature of 28.4 °C and we can compute the specific heat of the metal as shown below:

Plugging the values in and since the density of water is 1.00 g/mL so the mass is 80.0g, we obtain:

Best regards!
Throw it in the ocean lol
Answer:
0.48
Explanation:

because we are looking for I which is current we say
I = 12÷25 which is 0.48.
the answer is 0.0693769. 6.02x10^21 x6.94/ 6.022x10^23 is the formua you would use.