Answer:
See explanation.
Explanation:
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In this case, according to the described chemical reaction, we first write the corresponding equation to obtain:
Thus, we proceed as follows:
Part 1 of 3: here, since the molar mass of silver and copper (II) nitrate are 107.87 and 187.55 g/mol respectively, and the mole ratio of the former to the latter is 2:1, we can set up the following stoichiometric expression:
Part 2 of 3: here, the molar mass of copper is 63.55 g/mol and the mole ratio of silver to copper is 2:1, the mass of the former that was used to start the reaction was:
Part 3 of 3: here, the molar mass of silver nitrate is 169.87 g/mol and their mole ratio 2:2, thus, the mass of initial silver nitrate is:
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Stoichiomety:
1 moles of C + 1 mol of O2 = 1 mol of CO2
multiply each # of moles times the atomic molar mass of the compund to find the relation is weights
Atomic or molar weights:
C: 12 g/mol
O2: 2 * 16 g/mol = 32 g/mol
CO2 = 12 g/mol + 2* 16 g/mol = 44 g/mol
Stoichiometry:
12 g of C react with 32 g of O2 to produce 44 g of CO2
Then 18 g of C will react with: 18 * 32/ 12 g of Oxygen = 48 g of Oxygen
And the result will be 12 g of C + 48 g of O2 = 60 g of CO2.
You cannot obtain 72 g of CO2 from 18 g of C.
May be they just pretended that you use the law of consrvation of mass and say that you need 72 g - 18g = 54 g. But it violates the proportion of C and O2 in the CO2 and is not possible.
The IUPAC name for the organic compound CH2(OH)-CH2-CH(C2H5)-OH is Pentan-1,3-diol
This compound above belong to class of organic compound called the alkanols
<h3>What are organic compounds?</h3>
Organic compounds are compounds which contains carbon and hydrogen only.
Some few classes of organic compounds includes the following:
- Alkanes
- Alkenes
- Alkynes
- Alkanols
- Alkanals
- Alkanones
- Esters
- Ketones and other
So therefore, the IUPAC name for the organic compound is CH2(OH)-CH2-CH(C2H5)-OH is Pentan-1,3-diol
Learn more about organic compounds:
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Answer:
A) he equilibrium concentration of PH3 = 0.0432M
B) he equilibrium concentration of BCl3 = 0.0432M
C) what is the minimum mass of PH3BCl3(s) that must be added to the flask to achieve equilibrium = 1.69g
Explanation:
The detailed steps and appropriate calculation is as shown in the attached file.
