The question is typed wrong. Assuming the correct question is
How many liters of 0.98 M H2SO4 solution would react completely with 3.5 moles Ca(OH)2 ?
Answer:-
3.571 litres
Explanation:-
The balanced chemical equation for this reaction is
H2SO4 + Ca(OH)2 = CaSO4 + 2 H2O
From the balanced chemical equation we see that
1 mole of Ca(OH)2 reacts with 1 mol of H2SO4.
∴3.5 moles of Ca(OH)2 reacts with 1 x 3.5 / 1 = 3.5 mol of H2SO4.
Strength of H2SO4 = 0.98 M
Volume of H2SO4 required = Number of moles of H2SO4 / Strength of H2SO4
= 3.5 moles / 0.98 M
= 3.571 litre
Answer:
Explanation:
From the question we are told that:
pKa for Acetic Acid 
Therefore
For Equal Concentration of acetic acid and acetatic ion
Generally the Henderson's equation for pH value is mathematically given by
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Mass % of NaOH solution = 10 % (m/v)
Mass of NaOH required to prepare 1 L solution:
= 100 g NaOH
55.3C= 328.45K
255K= -18.5C
447K= 174.85C
-14C= 259.15K
