On oxidation of aldehydes produces carboxylic acid functional group.
The product of oxidation of aldehydes depends upon whether the reaction occur in acidic medium or alkaline condition.
If oxidation of aldehydes occurs under acidic condition the product is carboxylic acid but if oxidation of aldehydes occurs under alkaline condition then reduce as well as oxidized product obtained which is known as disproportional product.
The oxidation of aldehydes occur through potassium dichromate, potassium permanganate or many more. The oxidation of aldehydes in the presence of base is known as cannizzaro's reaction.
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D is the answer. The thermo works as an insulator minimizing the heat loss to the environment.
Answer:
Sr would be the limiting reactant
5 moles
Explanation:
Since the equation is a balanced equation, the coefficient shows how each substance relates to the other in terms of the number of moles.
Reactants would be those on the left hand side of the arrow, while the products would be found on te right and side of the arrow. In this question, the reactants would be Sr and O₂.
Limiting reactant is the reactant that is insufficient; meaning to say that there is not enough of that substance and thus the reaction cannot continue. The other reactant(s) that is not limiting is called the excess reactants.
From the balanced equation, 2 moles of Sr is needed to react with 1 mole of O₂. Thus, if we have 5 moles of each reactant, Sr would be the limiting reactant since for every 1 mole of O₂, there has to be 2 moles of Sr in order for the reaction to proceed. Thus, if we have 5 moles of O₂, we would need 10 moles of Sr.
When we work out the amount of products formed, we look at the number of moles of the limiting reactant. This is because the limiting reactant determines how much is being reacted, while the excess number of moles of the excess reactant will remain unreacted.
For every 2 moles of Sr reacted, 2 moles of SrO would be produced. This means that the mole ratio of Sr to SrO is 1:1. Thus, since 5 moles of Sr has been reacted, 5 moles of the product (SrO) would be produced.
Answer:
Option C = 6 of carbon react with 16 g of oxygen.
Explanation:
In given question it is stated that 12 g of carbon react with 32 g of oxygen to produce carbon dioxide. The other combination option c is also true because in this, the quantity of both reactant is just half from the given quantity. Which means that if 100 % product is obtained from the 12 g of carbon and 32 g of oxygen then by taking the half amount of reactant the product will be half i.e 50% .
This combination is true because the ratio of both reactant are justified.
Carbon 12g + Oxygen 32g → carbon dioxide
C : O 1 : 2.6
Option C:
Carbon ( 12/2 =6g ) + Oxygen (32/2 = 16g) → Carbon dioxide
C : O 1 : 2.6
Answer:
For the most part radish seed growth is best when they are planted in cool soil; early spring or fall are the preferred seasons for many varieties. Next, be sure to get the soil in good shape before planting – loose, full of seasoned organic material, but not overly fertile. Moisture and soil depth must be right, too.
Explanation:
