Answer:
- AgNO₃ (aq) + KCl (aq) → AgCl (s) + KNO₃ (aq)
Explanation:
In a <em>solubility table</em> you find:
- AgNO₃ (silver nitrate) is highly soluble
- KCl (potassium chloride) is soluble
- AgCl (silver chloride) is insoluble
- KNO₃ (potassium nitrate) is soluble
In a chemical equation the states of soluble compounds is identified as aqeous, using the letter "aq" in parenthesis, and the state of insoluble compounds is identified as solid, using "s" in parenthesis.
Then, the reaction showing the states of the reactants and products is:
- AgNO₃ (aq) + KCl (aq) → AgCl (s) + KNO₃ (aq)
Balanced chemical reaction: A + 5C ⇄ AC₅.
<span>[A] = 0.100 M; equilibrium concentration.
</span><span>[C] = 0.0380 M.
</span>[AC₅] = 0.100 M.
Kf = [AC₅] / ([A] · [C]⁵).
Kf = 0.100 M ÷ (0.100 M · (0.0380 M)⁵.
Kf = 12620658.54 = 1,26·10⁷.
<span>The formation constant can be calculated when </span>chemical equilibrium is reached, when the forward reaction rate is equal to the reverse reaction rate.
Reaction of option c produces precipitate.
Rhodium on reacting with potassium phosphate produces rhodium phosphate which remain in solution due to low lattice energy for rhodium phosphate.
Niobium on reacting with lithium carbonate produces niobium carbonate and it will remain in aqueous form.
Cobalt on reacting with zinc nitrate produces cobalt nitrate. This, Co(NO3 )2 is insoluble precipitate and settles at bottom whereas zinc ion will remain in solution as follows:

Potassium ion on reacting with sodium sulfide produces potassium sulfide which remain in solution
Answer:
Explanation:
We will need a balanced equation with moles, so let's gather all the information in one place.
CH₃C₆H₄NH₂·HCl + (CH₃CO)₂O ⟶ CH₃C₆H₄NHCOCH₃ + junk
V/mL: 70.
c/mol·L⁻¹: 0.167
For simplicity in writing , let's call p-toluidine hydrochloride A and N-acetyl-<em>p</em>-toluidine B.
The equation is then
A + Ac₂O ⟶ B + junk
1. Moles of A

2. Moles of B
The molar ratio is 1 mol B:1 mol A
Moles of B = moles of A = 12 mmol = 0.012 mol

Answer:
The molar mass of
is 96.8 g/mol
Explanation:
The given molecular formula - 
Individual molar masses of each element in the compound is as follows.
Molar mass of nitrogen - 14.01 g/mol
Molar mass of of hydrogen = 1.008g/mol
Molar mass of carbon = 12.01 g/mol
Molar mass of oxygen =16.00 g/mol
Molar mass of
is
![2\times[1(14.01)+4(1.008)]+1(12.01)+3(16.00)= 96.8g/mol](https://tex.z-dn.net/?f=2%5Ctimes%5B1%2814.01%29%2B4%281.008%29%5D%2B1%2812.01%29%2B3%2816.00%29%3D%2096.8g%2Fmol)
Therefore,The molar mass of
is 96.8 g/mol