(x^15)(x^-3) = x^(15 + (-3)) = x^12
n = 12
Answer:
A: -5, -1, 5, 6, 7
B: -12.4, -12.1, -2, 1/2, 12, 12 1/4, 12 1/2
Answer:
n = 13.
Step-by-step explanation:
Slope of the line = (10-1)/3-0) = 3
So the equation of the line is:
y - 1 = 3(x - 0)
y = 3x + 1
When x = 4 y = n, so:
n = 3(4) + 1 = 13.
n = 13.
Answer:

Step-by-step explanation:
We will use the standard formula for half-life:

Where A₀ is the initial amount, a is the half-life, d is the time for one half-life, and t is the number of days.
So, we will substitute 1/2 for a and 24.3 for d. This yields:

We have a 3 gram sample. Therefore, our initial amount A₀ is 3:

And we want to find the remaining sample after 10 days. So, t=10. Substitute:

Use a calculator. So:

Therefore, for a 3 gram sample of Phosphorous-32 with a half-life of 24.3 days, after 10 days, there will be approximately 2.255 grams remaining.
I’m pretty sure the coordinates of the new point are (2, 6)! :)
(Also, could I have brainliest?)