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Iteru [2.4K]
3 years ago
13

can anyone please help me I am struggling?? It’s 9th grade algebra 1 average rate of change comparison

Mathematics
1 answer:
gtnhenbr [62]3 years ago
5 0

Answer:

a) 2 b) 1 c) 7/6

Function a(x) = 2x + 3 has the greatest rate of change

Step-by-step explanation:

a(x) = 2x + 3

2(-1) + 3 = 1 (-1,1)

2(2) + 3 = 7 (2,7)

\frac{7-1}{2-(-1)} = 6/3

=2

b(x) = x^2 - 1

(-1)^2 - 1 = 0 (-1, 0)

(2)^2 - 1 = 3 (2,3)

\frac{3-0}{2-(-1)} = 3/3

=1

c(x) = 2^x + 1

2^(-1) + 1 = 1.5 (-1, 1.5)

2^(2) + 1 = 5 (2,5)

\frac{5-1.5}{2-(-1)} = 3.5/3 or 7/6

=7/6

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NEED IT ASAP What is the value of x in the diagram below? A.18/ ROOT 3 B.18 ROOT 2/ROOT 3 C.18 ROOT 3/ ROOT 2 D. 18 ROOT 2
Ostrovityanka [42]

Answer:

x = B. 18 ROOT 2/ROOT 3

Step-by-step explanation:

There are two Triangles in the diagram above.

Step 1

We would solve for Triangle A First

Using Trigonometric function Cosine

cos θ = adjacent /hypotenuse

θ = 30°

Adjacent = 9 units

Hypotenuse = unknown

cos 30= 9/ Hypothenuse

Cross Multiply

cos 30 × Hypotenuse = 9

Hypotenuse = 9 / cos 30

cos 30 in surd form = √3/2

Hypotenuse = 9/√3/2

Hypotenuse = 9 × 2/√3

= 18/√3 units

Step 2

We would solve for the upper triangle = Triangle B

We are looking for x

θ = 45°

For Triangle B, the Hypotenuse we solved for in Triangle A is equivalent to the adjacent in Triangle B

Therefore ,

Hypotenuse for Triangle A = Adjacent side for Triangle B

θ = 45°

Adjacent = 18/√3 units

Hypotenuse = x = unknown

We would solve for this using Trigonometric function cosine

cos 45 = 18/√3 units / Hypothenuse

Cross Multiply

cos 45 × Hypotenuse = 18/√3 units

Hypotenuse = 18/√3 units / cos 45

cos 45 in surd form = 1/√2

Subtituting, we have

Hypotenuse (x) = 18/√3 units / 1/√2

Hypotenuse (x) = 18/√3 units ×√2/1

= 18× √2/ √3 units

= 18 √2/√3 units

Therefore x = Option B. 18 ROOT 2/ROOT 3

3 0
3 years ago
An engineer is trying to design a runway for an airport. He knows that airplanes have the ability to accelerate at 3.3 m/s ^ 2 a
chubhunter [2.5K]

Answer:

The proposed 1600 meters runway length is not long enough

Step-by-step explanation:

The given parameters are;

The amount by which a plane can accelerate = 3.3 m/s²

The time it takes for a plane to lift off the ground = 35 seconds

The length of the runway on the blueprint = 1,600 meters

Therefore, from the equation of motion for distance traveled, s, acceleration, a, and time taken, t, we have;

s = u·t + 1/2·a·t²

Where;

u = The initial velocity

t = 35 seconds

a = 3.3 m/s²

Given that all planes will start motion from rest, we have;

u = 0 m/s

Therefore;

s = 0 × 35 + 1/2 × 3.3 × 35² = 2021.25 meters

Which indicates that the length of the runway a plane would need for take off should be at least 2021.25 meters long, therefore, the blueprint's 1600 meters runway length is not long enough.

7 0
3 years ago
Help me solve this problem please
sergey [27]
The answer is y-4=-3(x-13)
5 0
3 years ago
Read 2 more answers
50. y=-3x+
Verdich [7]

the answer is 58.8 so i think these the answer

5 0
3 years ago
X = {(2, 3), (2, 4), (2, 5), (2, 6)} is x a function and why? no, each ordered pair in this list has the same first element. yes
Vesnalui [34]
For every input, there is one output
for every x there is one y
(x,y)

if x repeats with a differnt y, it's not a function
we see
(2,3) and (2,4) and all of them

no, not a function
<span>no, each ordered pair in this list has the same first element
answer is first one
</span>


6 0
3 years ago
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