Salt seems to dissappear when it is poured into water. Use mixture, solution, and dissolve to explain what happens.

Chemistry

1 answer:

fgiga [73]3 years ago

8 0

The salt desolves into the water which forms a solution which is called a mixture.

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For each of the salts below, match the salts that can be compared directly, using Ksp values, to estimate solubilities.

Anni [7]

Answer:

1 - Salts required that can be compared directly, using Ksp values, to estimate solubilities for copper (II) sulfide are - $CaSO_3$ (Option b) , $BaCrO_4$ (Option c) and $CaS$ (Option d)

2 - Salts that can be compared directly, using Ksp values, to estimate solubilities for zinc hydroxide are - $Mg(OH)_2$ (Option a)

Explanation:

$K_s_p$ values can be used to compare the solubility of salts that produce ions in a 1:1 ratio.

$CuS$ {copper (II)sulfide} dissociates with ions in ratio 1:1 .

Because the salts $CaSO_3$ , $BaCrO_4$ and $CaS$ have a 1:1 ion ratio, the solubilities of options b, c, and d can be compared to salt 1.

$K_s_p$ Values can be used to compare the solubility of salts that produce ions in a 1:2 or 2:1 ratio.

2. $Zn(OH)_2$ dissociates into ions in ratio 1:2 .

Because the ions in the salt $Mg(OH)_2$ are in a 1:2 ratio, the solubility of salt 2 can be compared to that of salt 'a'.

Hence , Salt 1 is matched with options b , c , d.

Salt 2 is matched with option a.

4 0

3 years ago

According to Newton's third law, forces come in pairs. There is_____and an equal and opposite_____.

hichkok12 [17]

According to Newton's third law, forces come in pairs. There is action-reaction force and an equal (in size - action force) and opposite in direction (reaction force).

<u>Explanation:</u>

On the off chance, when item A applies a force on item B, at that point item B must apply a force of equivalent size and inverse bearing back on object A. This Newton's third law speaks to a specific balance in nature: forces consistently happen two by two.

And, one body can't apply a force on another without encountering a force itself. Now and again, allude to this law freely as activity response, where the force applied is the activity and the force experienced as a result is the response.

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3 years ago

A 0.8115 g sample of HCl was placed into a 50 mL volumetric flask and the sample was thoroughly dissolved in water to make 50 mL

inysia [295]

Answer:

Molarity of NaOH solution is 1.009 M

Explanation:

Molar mass of HCl is 36.46 g/mol

Number moles = (mass)/(molar mass)

So, 0.8115 g of HCl = $\frac{0.8115}{36.46}moles$ HCl = 0.02226 moles HCl