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tensa zangetsu [6.8K]
3 years ago
7

Indique el valor de los números n,l,m y s para el último electrón de ₇N.(1 pt c/u) n = _____ l = _____ m = _____ s =_____

Chemistry
1 answer:
tia_tia [17]3 years ago
6 0

Answer:

n = 2

l = 1

m = 1

s = +1/2

Explanation:

₇N tiene la configuración electrónica;

1s2 2s2 2p3

Esto implica que este último electrón tiene los siguientes números cuánticos;

n = 2

l = 1

m = 1

s = +1/2

Este último electrón estará en un orbital de 2pz como lo muestran los números cuánticos enumerados anteriormente.

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Answer:

\boxed {\boxed {\sf v\approx  1.79 \ cm^3}}

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v=\frac{m}{d}

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m=38.5 \ g \\d= 21.5 \ g/cm^3

Substitute the values into the formula.

v=\frac{38.5 \ g}{ 21.5 \ g/cm^3}

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v=1.79069767 \ cm^3

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v\approx  1.79 \ cm^3

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  • Question 19: the three are molecular compounds.
  • Question 20: CuSO₄.5H₂O

Explanation:

<em>Question 19.</em>

  • C₂H₄
  • HF
  • H₂O₂

All of them are the combination of two kinds of different atoms in fixed proportions.

  • C₂H₄: two carbon atoms per four hydrogen atoms
  • HF: one hydrogen atom per one fluorine atom
  • H₂O₂: two hydrogen atoms per two oxygent atoms

Thus, they all meet the definition of compund: a pure substance formed by  two or more different elements with a definite composition.

Molecular compounds are formed by covalent bonds and ionic compounds are formed by ionic bonds.

Two non-metal elements, like H-F, C - C, C - H, H-O, H - H, and O - O will share electrons forming covalent bonds to complete their valence shell. Thus, the three compounds are molecular and not ionic.

<em>Question 20. </em>Formula of copper(II) sulfate hydrate with 36.0% water.

Copper(II) sulfate is CuSO₄. Its molar mass is 159.609g/mol

Water is H₂O. Its molar mass is 18.015g/mol

Calling x the number of water molecules in the hydrate, the percentage of water is:

       \dfrac{18.015x}{18.015x+159.609}=36\%\\ \\ \\ \dfrac{18.015x}{18.015x+159.609}=0.36

From which we can solve for x:

      18.015x=6.4854x+57.45924\\ \\ 11.5296x=57.45924\\ \\ x\approx4.98\approx5

Thus, there are 5 molecules of water per each unit of CuSO₄, and the formula is:

  • CuSO₄.5H₂O
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