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The Lewis structures for formate ion and carbon dioxide are shown in the attached pictures. As you can see, the formate ion consists of one C=O bond and one C-O bond, while carbon dioxide has two C=O bonds. Double bonds are weaker, hence, longer compared to single bonds. Therefore, the C-O bonds in the formate ion is shorter than those in carbon dioxide.
The empirical formula is obtained by calculating the mole ratios of the atoms in the elements.
The number of moles =mass/ R.A.M
For hydrogen, no. of moles=8/1=8
For oxygen, no. Of moles=64/16=4
The tabular solution is attached.
Explanation:
A source Emits a sound and is represented by the red dot in this map. Four people are located and the source and the circle represent the sound wave.
As the source moves west which person hears the highest pitch
person B
Answer:
Molybdenum
Explanation:
Molybdenum is a chemical element with the symbol Mo and an atomic number of 42. This implies a total of 42 electrons in its orbital.
The atomic weight of Mo is 95.94g/mol.
Using the sublevel notation system, the electrons can be filled into the orbitals as shown below:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d⁴
The ending configuration of this element is therefore 4d⁴