Answer is: solution of electrolyte will have lower freezing point than solution of nonelectrolyte.
This is because salt solution has more particles in of sodium chloride (sodium and chlorine ions) than in same concentration of glucose. Electrolytes better separates into particles in water because of their ionic bond.<span>
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To dilute a solute in a solution, it is necessary to add a proper solvent for the reaction to occur, and adding more solvent will cause the solution to dilute even more, therefore the best answer will be letter B
Answer:
Explanation:The final homogenous solution, after cooling it to 40°C, will contain 47 g of potassium sulfate disolved in 150 g of water, so you can calculate the amount disolved per 100 g of water in this way:
[47 g of solute / 150 g of water] * 100 g of g of water = 31.33 grams of solute in 100 g of water.
So, when you compare with the solutiblity, 15 g of solute / 100 g of water, you realize that the solution has more solute dissolved with means that it is supersaturated.
To make a saturated solution, 15 grams of potassium sulfate would dissolve in 100 g of water.
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Answer:
4
Explanation:
because it has 3 carbons and 6 hydrogen
hope this helps :)
Answer:
1. 0.22 mol/dm³
2. 0.23 mol/dm³
Explanation:
Molarity: This can be defined as the concentration of a substance in mol per dm³
1.
M = n/v ...................... Equation 1
M = molarity of methanol, n = number of mole of methanol, v = volume of the solvent/water/solution.
<em>n = g/m.m</em>
<em>Where g = mass of methanol, m.m = molar mass of methanol.</em>
<em>g = 6.4 g, m.m = 32 g /mole.</em>
<em>n = 6.4/32 = 0.2 mole</em>
<em>and ,</em>
<em>v = m/d </em>
<em>Where m = mass of water, d = density of water</em>
<em>m = mass of 50 moles of water = 18×50 = 900 g.</em>
d = 1000 g/dm³.
v = 900/1000 = 0.9 dm³
Substituting the value of v and n into equation 1
M = 0.2/0.9
M = 0.22 mol/dm³
2.
M = n/v
v = volume of the solution
v = (mass of methanol + mass of water in the solution)/density of the solution
v = [(900+6.4)/1000]/1.03
v = 0.9064/1.03
v = 0.88 dm³
n = 0.2 mole
Therefore,
M = 0.2/0.88
M = 0.23 mol/dm³
