QUESTION 3
The sum of the interior angles of a kite is .
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But the two remaining opposite angles of the kite are congruent.
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QUESTION 4
RH is the hypotenuse of the right triangle formed by the triangle with side lengths, RH,12, and 20.
Using the Pythagoras Theorem, we obtain;
QUESTION 5
The given figure is an isosceles trapezium.
The base angles of an isosceles trapezium are equal.
Therefore
QUESTION 6
The measure of angle Y and Z are supplementary angles.
The two angles form a pair of co-interior angles of the trapezium.
This implies that;
QUESTION 7
The sum of the interior angles of a kite is .
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.
.
.
But the two remaining opposite angles are congruent.
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.
.
QUESTION 8
The diagonals of the kite meet at right angles.
The length of BC can also be found using Pythagoras Theorem;
QUESTION 9.
The sum of the interior angles of a trapezium is .
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But the measure of angle M and K are congruent.
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Answer:
15=13
Step-by-step explanation:
15=-6 you solve the left side, 7+6 which is 15?
15=-6 =
7+6 = 13
15=13
i'm not sure...
Answer:
15 classrooms
Step-by-step explanation:
y/x = k
6.4/4 = 1.6
11.2 / 7 =1.6
16/10 = 1.6
20.8 /13 =1.6
This is a direct variation and the constant is 1.6
y=1.6x
Answer:
2.4 bags
Step-by-step explanation:
Uh you can keep your brains.
Using the data table, we get:
1, 2, 2, 3, 4 as our data.
Finding the mean:
(1+2+2+3+4)÷5=
12÷5=
2.4 bags