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Elenna [48]
3 years ago
6

The water cycle would not be possible without ______ and ________.

Chemistry
1 answer:
ipn [44]3 years ago
4 0

Answer:

I think it's 4

Explanation:

but I don't really remember the water cycle

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2. What is the mass of 5.33 x 10 moles of aluminum hydroxide?​
bearhunter [10]
<h3>Answer:</h3><h3>1865.5g</h3><h3>Explanation:</h3><h3 /><h2> first the chemical formular for ammonium hydroxide is NH4OH</h2><h3>its molarmass is given as N=14H=1O=16 </h3><h3> so we have 14 +1(2) +16+1 =35</h3><h2>also no of moles = mass / molarmass</h2><h3> we have 5.33×10 = mass/35 </h3><h2>therefore mass = 35 ×5.33×10 = 1865.5g</h2>
8 0
3 years ago
To show the electron configuration for an atom, when would it be better to use an orbital notation than to use a written configu
anzhelika [568]
I believe it would be better to use an orbital designation than the written configuration, if the number of electrons in the ground state of the atom are quite high for the given element, as above 50, for instance.

This saves space and also one can see the discrete quantized energy levels associated with the subshells of the main energy levels if written in orbital designation.
7 0
3 years ago
Read 2 more answers
What is the pressure of the gas if we have 3.50 moles of helium at -50.0°C
Marianna [84]

Answer:

259.6kPa

Explanation:

because it is big

7 0
3 years ago
Which of the following methods can be used to separate salt and iron
DochEvi [55]

Answer:

since iron is magnetic your best choice would be to use magnetism.

6 0
3 years ago
Read 2 more answers
What volume in milliters would give 12.0 grams of NaOH from a 2.0 M NaOH solution?
zavuch27 [327]

Answer:

V = 150 mL

Explanation:

Hello!

In this case, since the molarity of a solution is computed via:

M=\frac{n}{V}

Whereas we are asked to compute the volume:

V=\frac{n}{M}

Thus, we first compute the moles in 12.0 g of NaOH as its molar mass is about 40.0 g/mol:

n=\frac{12.0g}{40.0g/mol}=0.3mol

Thus, at first instance, the volume liters is:

V=\frac{0.3mol}{2.0mol/L} \\\\V=0.15L

Which in milliliters is:

V=0.15L*\frac{1000mL}{1L}\\\\V=150mL

Best regards!

5 0
3 years ago
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