As chlorine has seven electrons in its outer most shell so to complete its octet it has to gain an electron and when it gain an electron it will become an anion that is negatively charged
so in my opinion and what a conclude is that the option B is correct for the above statement
Answer: -
0.1 ml of bleach should be added to each liter of test solution.
Explanation:-
Let the volume of bleach to be added is B ml.
Density of stock solution = 1.0 g/ml
Mass of stock solution = Volume of stock x density of stock
= B ml x 1.0 g/ml
= B g
Amount of NaOCl in this stock solution = 5% of B g
=
x B g
= 0.05 B g
Now each test solution must be added 5 mg/l NaOCl.
Thus each liter of test solution must have 5 mg.
Thus 0.05 B g = 5 mg
= 0.005 g
B = 
= 0.1
Thus 0.1 ml of bleach should be added to each liter of test solution.
The easiest answer and most relevant is because it didn't sink
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True... there are better ways using less materials and printing is that