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const2013 [10]
3 years ago
11

Please match each cofactor with its function. 1) thiamine pyrophosphate A) CO2 activation/transfer 2) coenzyme A B) oxidation/re

duction 3) biotin C) activation of aldehydes 4) NAD D) acyl group transfer
Chemistry
1 answer:
yanalaym [24]3 years ago
8 0

Answer:

1) thiamine pyrophosphate -activation of aldehydes

2) coenzyme A -acyl group transfer

3) biotin -CO2 activation/transfer

4) NAD -oxidation/reduction

Explanation:

1. Thiamine pyrophosphate: This is a derivative of Vitamin B1 also known as thiamine. It contains a pyrimidine group linked to the thiazole ring. This connection is further linked to the pyrophosphate group. It functions as a coenzyme in all reactions involving alpha-keto acids. This produces activated aldehydes that could be subject to oxidation.

2. Coenzyme A: This cofactor is a thiol that reacts with carboxylic acids to form thioesters. In so doing, it carries the acyl group. In this condition, it can also be referred to as acyl CoA.

3. Biotin: Also known as Vitamin B7, biotin consists of an ureido ring merged with tetrahydrothiophene. The ureido ring contains the CO2 that can be transferred or activated. Five carboxylase enzymes use biotin as a cofactor in processes such as fat synthesis, glucose generation and the breakdown of sugar.

4. NAD:  Nicotinamide adenine dinucleotide consists of two dinucleotides connected to each other at their phosphate groups. NAD exists in two states which are the NAD+ and NADH states. These two states serve as oxidizing and reducing agents respectively. The oxidizing agent becomes reduced to NADH after accepting electrons from other compounds. NADH donates an electron and becomes oxidized to NAD+.

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Answer : The incorrect option is, (d) NH_4^+/NH_2^-

Explanation :

According to the Bronsted Lowry concept, Bronsted Lowry-acid is a substance that donates one or more hydrogen ion in a reaction and Bronsted Lowry-base is a substance that accepts one or more hydrogen ion in a reaction.

Or we can say that, conjugate acid is proton donor and conjugate base is proton acceptor.

(a) The equilibrium reaction will be,

HF+H_2O\rightleftharpoons F^-+H_3O^+

In this reaction, HF is an acid that donate a proton or hydrogen to H_2O base and it forms F^- and H_3O^+ are conjugate base and acid respectively.

In this reaction, HF/F^- are act as a conjugate acid-base.

(b) The equilibrium reaction will be,

HClO+H_2O\rightleftharpoons ClO^-+H_3O^+

In this reaction, HClO is an acid that donate a proton or hydrogen to H_2O base and it forms ClO^- and H_3O^+ are conjugate base and acid respectively.

In this reaction, HClO/ClO^- are act as a conjugate acid-base.

(c) The equilibrium reaction will be,

H_2O+H_2O\rightleftharpoons OH^-+H_3O^+

In this reaction, H_2O is an acid that donate a proton or hydrogen to

In this reaction, H_2O/OH^- are act as a conjugate acid-base.

(d) The equilibrium reaction will be,

NH_4^++H_2O\rightleftharpoons NH_3+H_3O^+

In this reaction, NH_4^+ is an acid that donate a proton or hydrogen to H_2O base and it forms NH_3 and H_3O^+ are conjugate base and acid respectively.

In this reaction, NH_4^+/NH_3 are act as a conjugate acid-base.

(e) The equilibrium reaction will be,

H_3O^++H_2O\rightleftharpoons H_2O+H_3O^+

In this reaction, H_3O^+ is an acid that donate a proton or hydrogen to H_2O base and it forms

In this reaction, H_3O^+/H_2O are act as a conjugate acid-base.

From this we conclude that that, NH_4^+/NH_2^- pairs of acids and conjugate bases is incorrectly labeled or incorrectly matched.

Hence, the incorrect option is, (d) NH_4^+/NH_2^-

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