Answer: Li < Na < K is the answer
Explanation:
Formula for water is H20 and there are 5 mol water. 2 mol of hydrogen per 1 mol water so 5 mol of water times 2 mol hydrogen will give you 10 mol of hydrogen.
Same process with oxygen except 1 mol of oxygen per mol of water. So 5 mol water times 1 mol of oxygen will give you 5 mol of oxygen.
The first step is to make a balanced chemical equation.
2AgNO3 + CaCl2 ---> 2AgCl + Ca(NO3)2
Molecular Weights:
CaCl2 = 110.98 g/mol
AgNO3 =170.01
AgCl: 143.45 g/mol
Volume:
CaCl2: 30.0mL=0.03L
AgNO3: 15.0mL=0.015 L
Solving for the limiting reactant one needs to get the mols CaCl2 and mols AgNO3:
CaCl2: 0.150M(mol/L) * 0.03L = 0.0045 moles
AgNO3: 0.100M*0.015L = 0.0015 moles
Since the stoichiometric ratio of AgNO3 to CaCl2 is 2:1
0.0015 mols AgNO3 *(1 mol CaCl2/ 2 mols AgNO3) = 0.00075 mols CaCl2
Since the answer is lesser than CaCl2 then the limiting reactant is AgNO3.
To get the mass of AgCl one will do a stoichiometric calculation with respect to the limiting reactant, AgNO3.
0.0015 moles AgNO3 *
<h3>
Answer:</h3>
45°C
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Explanation:</h3>
We are given;
- Quantity of heat = 1.95 kJ
- Mass of lead = 500 g
- Initial temperature = 15° C
- heat capacity of lead is 130 J/kg°C
We are required to calculate the final temperature;
- We need to know that the quantity of heat is given by the formula;
Q = mass,m × specific heat,c × Change in temperature,ΔT
ΔT = final temperature - initial temperature
We can rearrange the formula to calculate the change in temperature
ΔT = Q ÷ (m×c)
Therefore;
ΔT = 1950 J ÷ (0.5 kg × 130 J/Kg°C)
= 30°C
But,
Final temperature = ΔT + Initial temperature
= 15°C + 30°C
= 45°C
Therefore, the final temperature is 45°C
Co2 is made of carbon ( atomic mass: 12) and oxygen (atomic mass : 16)
First : mass of 1 C atom + mass of 2 O atom = 12+(16*2)=44 amu so 1 mole CO2 =44 grams then 2.5 mole CO2 =44*2.5 =110 grams
So the answer is 110 grams