Answer:
Pressure for H₂ = 11.9 atm
Option 5.
Explanation:
We determine the complete reaction:
2Al(s) + 6HCl(aq) → 2AlCl₃(aq) + 3H₂(g)
As we do not know anything about the HCl, we assume that the limiting reactant is the Al and the acid is the excess reagent.
Ratio is 2:3.
2 moles of Al, can produce 3 moles of hydrogen
Therefore 4.5 moles of Al must produce (4.5 . 3) / 2 = 6.75 moles
Now we can apply the Ideal Gases law to find the H₂'s pressure
P . V = n . R . T → P = (n . R .T) / V
We replace data: (6.75 mol . 0.082L.atm/mol.K . 300K) / 14L
Pressure for H₂ = 11.9 atm
Answer:
because it is first before the small intestine and it digests food first
Explanation:
It would be a combustion reaction (B) because the products are carbon dioxide and water.
Answer:
we use: V = pi*(r^2)*h
V = 3.14*(12.0cm^2)*44.0 cm
V = 19895.04 cm^3
Therefore, mass = (8.90g/cm^3) * (19895.04 cm^3) = 177065.856 g
Explanation:
