1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elina [12.6K]
1 year ago
5

Consider the following statistic. As of January 2009, the USA has produced 60,000 metric tons of nuclear waste in 60 years of op

erating 104 nuclear power plants. On average, how much waste is produced by each plant on a monthly basis? 0. 8 tons per month 83. 3 tons per month 104 tons per month 866. 3 tons per month.
Chemistry
1 answer:
Korolek [52]1 year ago
4 0

Answer: A

Explanation:

You might be interested in
A chemical reaction is carried out in a closed container. the energy absorbed by the chemical reaction is 100 kj. What is the en
lubasha [3.4K]

Answer:

Option A

Explanation:

The total heat absorbed during the chemical reaction is the total heat released by the surrounding.

Net change of heat is equal to zero

Hence, the energy liberated from the air or the walls of the containers would be equal to the energy absorbed by the chemical reactions is equal to 100 Kj

Thus, option A is correct

8 0
2 years ago
Jesse travels 3.0 meters east and then turns and travels 4.0 meters north. What distance did Jesse travel? 1 m 5 m, northeast 7
boyakko [2]
7.0 meters because 3.0+4.0=7 
3 0
3 years ago
Read 2 more answers
What mass of oxygen (O2) forms in a reaction that forms 15.90 g C6H12O6? (Molar mass of O2 = 32.00 g/mol; molar mass of C6H12O6
Dafna11 [192]

The answer is: the mass of oxygen is 16.95 grams.

The overall balanced photosynthesis reaction:  

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂.  

m(C₆H₁₂O₆) = 15.90 g; mass of glucose.

n(C₆H₁₂O₆) = m(C₆H₁₂O₆) ÷ M(C₆H₁₂O₆).

n(C₆H₁₂O₆) = 15.9 g ÷ 180.18 g/mol.

n(C₆H₁₂O₆) = 0.088 mol; amount of glucose.

From chemical reaction: n(C₆H₁₂O₆) : n(O₂) = 1 : 6.

n(O₂) = 6 · 0.088 mol.

n(O₂) = 0.53 mol; amount of oxygen.

m(O₂) = 0.53 mol · 32.00 g/mol.

m(O₂) = 16.95 g; mass of oxygen.

5 0
3 years ago
Read 2 more answers
How many grams of MgCl2 (molar mass = 95.20 g/mol) will be formed from 25.6 mL of a 0.100 M HCL solution reacting with excess ma
lorasvet [3.4K]
The balanced equation for the above reaction is as follows;
Mg + 2HCl ---> MgCl₂ + H₂
stoichiometry of HCl to MgCl₂ is 2:1
we have been told that Mg is in excess therefore HCl is the limiting reactant 
number of HCl moles reacted - 0.100 mol/L x 0.0256 L = 0.00256 mol
according to molar ratio, number of MgCl₂ moles formed - 0.00256/2 
Therefore number of MgCl₂ moles formed - 0.00128 mol
mass of MgCl formed - 0.00128 mol x 95.20 g/mol = 0.122 g
3 0
2 years ago
Read 2 more answers
in order to decrease the freezing point of 500. g of water to 1.00° c how many grams of ethylene glycol (C2H602)must be added (K
sesenic [268]

Answer:

if wrong sorry ok????

6 0
2 years ago
Other questions:
  • List five physical properties?
    13·2 answers
  • Which of the following is considered applied research?
    15·1 answer
  • Are the intersection of any two half-planes necessarily a half-plane
    9·1 answer
  • Any substance composed of two or more elements that are chemically combined in a fixed proportion is
    5·1 answer
  • Iridium is a component of cosmic dust that rains down upon the earth at a constant rate. Why did Luis Alvarez suggest measuring
    9·2 answers
  • Compare the the volumes and densities of two pieces of lead: one with a mass of 25 g and the other with a mass of 75 g.
    12·1 answer
  • Anions are those elements on the upper right side of the periodic table, excluding the Noble gases, that gain electrons when the
    14·1 answer
  • View the video clip below and answer the question.
    15·2 answers
  • Name two metals which will not liberate hydrogen from<br>dilute tetraoxosulphate(vi) acid.​
    15·1 answer
  • What are the sun atomic particles!
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!