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AlladinOne [14]
4 years ago
14

What does the path of an object look like when it is in uniform motion ?

Physics
1 answer:
alexandr1967 [171]4 years ago
5 0
In uniform motion, the path is a straight line, and the object r moving along it at a constant speed.
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What determines an object’s velocity?
joja [24]

Answer:

I think it's 3) speed and direction

8 0
3 years ago
Which was a common goal of Spanish and British explorers in the Southeastern region of North America?
slamgirl [31]

Answer:

B

Explanation:

To discover gold

6 0
3 years ago
what is the total distance traveled by a bike rider who rides for three hours at 40 km/hr and then two more hours at 50 km/hr?
marta [7]

Answer:

220 km

Explanation:

3 hours at 40 km/hr

40 km = 1 hour

40 km times 3 = 120 km

2 hours at 50 km/hr

50 km = 1 hour

50 times 2 = 100 km

Total distance

120 km + 100 km = 220 km

4 0
3 years ago
In a local bar, a customer slides an empty beer mug down the counter for a refill. The height of the counter is 1.46 m. The mug
Tresset [83]

Answer:

(a). The horizontal velocity is 1.46 m/s.

(b). The direction of the mug's velocity just before it hit the floor is 74.7° below the horizontal.

Explanation:

Given that,

Height of the counter = 1.46 m

Distance = 0.80 m

We need to calculate the time

Using equation of motion

s_{y}=ut+\dfrac{1}{2}gt^2

s_{y}=\dfrac{1}{2}gt^2

Put the value into the formula

1.46=\dfrac{1}{2}\times9.8\times t^2

t^2=\dfrac{1.46\times 2}{9.8}

t=\sqrt{\dfrac{1.46\times2}{9.8}}

t=0.545\ sec

Here, horizontal velocity is constant

(a). We need to calculate the velocity

Using formula of velocity

v_{x}=\dfrac{d}{t}

Put the value into the formula

v_{x}=\dfrac{0.80}{0.545}

v_{x}=1.46\ m/s

(b). We need to calculate the final velocity

Using equation of motion

v_{f}^2=u^2+2as

Put the value into the formula

v_{f}^2=0+2\times9.8\times1.46

v_{f}=\sqrt{28.616}

v_{f}=5.34\ m/s

The velocity is 5.34 m/s downward.

We need to calculate the direction

Using formula of direction

\tan\theta=\dfrac{v_{y}}{v_{x}}

\theta=\tan^{-1}(\dfrac{5.34}{1.46})

\theta=74.7^{\circ}

Hence, (a). The horizontal velocity is 1.46 m/s.

(b). The direction of the mug's velocity just before it hit the floor is 74.7° below the horizontal.

5 0
4 years ago
2. A 3 kg ball is thrown downward at 4 m/s from a height of 1.5 m. a. What is the kinetic energy of the ball as it leaves the th
ludmilkaskok [199]

Answer:

a) 24 J

b) Gravitational Force

c) 45 J

d) 0

e) 6.782m/s

Explanation:

a) m = 3kg

v = 4m/s

h = 1.5m

KE = ?

0.5 * 3 * 16 = 24J

b) Gravitational force

c) F = ma = 3 * 10 = 30N

Work done = Force * distance = 30 * 1.5 = 45J

d) Final Kinetic Energy of the ball is zero because the ball eventually stops moving

e) velocity of ball as it strikes the ground = v

v^{2} - u^{2} = 2as where

v is the velocity as it strikes the ground

u is the initial velocity

a is acceleration

s is the distance

Now since the ball is thrown downwards, a is positive because the velocity of the ball is increasing as the gravitational force acts on it

u = 4m/s

a = 10

s = 1.5

=>  v = \sqrt{2as + u^{2} }

= \sqrt{(2*10*1.5) + 16}

= \sqrt{46} = 6.782m/s

3 0
3 years ago
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