Question

Two trains, each having a speed of 28 km/h, are headed at each other on the same straight track. A bird that can fly 60 km/h flies off the front of one train when they are 66 km apart and heads directly for the other train. On reaching the other train it flies directly back to the first train, and so forth. (We have no idea why a bird would behave in this way.) What is the total distance the bird travels before the trains collide?

Answer 1

Answer:

The value is $D = 70.71 \ km$

Explanation:

From the question we are told that

The speed of each train is $v = 28 \ km/h$

The speed of the bird is $v_1 = 60 \ km/h$

The distance between the trains is $d = 66 \ km$

Generally the time taken before the collision occurs is mathematically represented as

$t = \frac{d}{2 * v}$

=> $t = \frac{66 }{2 * 28}$

=> $t = 1.18 \ h$

The total distance covered by the bird is mathematically represented as

$D = v_1 * t$

=>   $D = 60 * 1.18$

=>   $D = 70.71 \ km$