Regards!
Boyle's law, which summarizes these observations, states that: the volume of a certain amount of gas, which is maintained at a constant temperature, is inversely proportional to the pressure exerted, which is summarized in the following expression:
P.V = constant or P = 1 / V
Example:
An inflated balloon with a volume of 0.55L at sea level (1.0 atm) is allowed to rise to a height of 6.5 km, where the pressure is about 0.40 atm.
Assuming that the temperature remains constant, what is the final volume of the balloon?
Reasoning and solution:
Note that the number of moles and the temperature of the gas remain constant, so Boyle's law is used. From the equation:
P1V1 = P2 V2
Where P1 = 1 atm, V1 = 0.55L and P2 = 0.40 atm, as well
V2 = V1 x (P1 / P2) = 0.55 L x (1 atm / 0.40 atm) = 1.4 L
When the pressure is reduced (at a constant temperature), the volume increases. The final volume is greater than the initial volume, so the answer is reasonable.
At decomposition of solid substance with formation of gas leads to increase in an entropy. For example,
60°C
NH₄NO₂(s) = N₂(g) + 2H₂O(l)
true
The answer is c I’m pretty sure that’s what it says on other sources
Answer:
a
Explanation:
Each oxygen molecule has 2 hydrogen molecules
Al = 26.981539u which rounds up to 27u
Ca= 40.078u which sounds to 40u
Sodium= 22.989769 which rounds up to 23u
Potassium= 39.0983u which rounds to 39u
Nitrogen= 14.0067u which rounds to 14u
Silicon= 28.0855 u which rounds to 28u
Iron= 55.845 u which rounds to 56u
Hydrogen= 1.00784 u which rounds to 1
I hope this helps!!