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salantis [7]
3 years ago
7

Can someone help with this please?

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
4 0

Answer:

y-intercept → (-5)

Slope → 4

Equation → y = 4x - 5

Step-by-step explanation:

From the table attached,

y - intercept → Output value at x = 0

y = -5

Slope = \frac{y_2-y_1}{x_2-x_1}

          = \frac{-13-(-9)}{-2-(-1)}

          = \frac{-13+9}{-2+1}

          = \frac{-4}{-1}

          = 4

m = 4

Equation of a line is given by,

y = mx + b

Here, m = Slope

b = y-intercept

Therefore, equation of the line will be,

y = 4x + (-5)

y = 4x - 5

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Pls help need it done pls
Harman [31]

Answer:

1/4 +m = 2/3

Step-by-step explanation:

3 0
3 years ago
The first 5 terms of a sequence are shown below:
nirvana33 [79]

Step-by-step explanation:

To find the formula for the nth term ,

First , find the common difference or common ratio.

Common difference =

T_2-T_1 \\  - 2 - 3 \\  =  - 5

Common ratio =

T_2/T_1 \\  \frac{ - 2}{3}

The common difference applies to the other given numbers for example :

T_3- T_2  =  - 7 - ( - 2) \\  =  - 7 + 2 =  - 5

this proves that it is an arithmetic sequence and the given formula for the nth term of an arithmetic sequence is

T_n =a(n-1)d

Where n = no of terms

a= first term

d= common difference

6 0
3 years ago
What is the slope of the line passing through the points (−3, −5) and (−1, −6)
inessss [21]

slope = (y2-y1)/(x2-x1)

m= (-6--5)/(-1--3)

m = (-6+5)/(-1+3)

m=-1/2

4 0
3 years ago
If you help me with this fast I will brain you.<br> Thanks.
irakobra [83]

Answer:

-2 and -6 is the correct answer

5 0
3 years ago
Find parametric equations for the sphere centered at the origin and with radius 3. Use the parameters s and t in your answer.
sdas [7]
Radius, r = 3

The equation of a sphere entered at the origin in cartesian coordinates is

x^2 + y^2 + z^2 = r^2 

That in spherical coordinates is:

x = rcos(theta)*sin(phi)
y= r sin(theta)*sin(phi)
z = rcos(phi)

where you can make u = r cos(phi) to obtain the parametrical equations

x = √[r^2 - u^2] cos(theta)
y = √[r^2 - u^2] sin (theta)
z = u

where theta goes from 0 to 2π and u goes from -r to r.

In our case r = 3, so the parametrical equations are:

Answer:
x = √[9 - u^2] cos(theta)
y = √[9 - u^2] sin (theta)
z = u
6 0
3 years ago
Read 2 more answers
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