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STatiana [176]
3 years ago
14

During oxidation, which of the following is true? A. Electrons are gained, so the oxidation number increases. B. Electrons are g

ained, so the oxidation number decreases. C. Electrons are given off, so the oxidation number increases. D. Electrons are given off, so the oxidation number decreases.
Chemistry
2 answers:
Anna11 [10]3 years ago
7 0

C) Electrons are given off, so the oxidation number increases.

I know because I took the test in Time4Learning and got a 100. :)

EastWind [94]3 years ago
6 0

Oxidation is when the overall charge (or oxidation number) increases.  The only way to increase an oxidation number is to lose an electron, thereby making the negative charges less.  The correct answer is C.

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A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. Calculate the pressure when the volume is 1.41 L and the
Vlad1618 [11]

A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

<h3>What is Combined Gas Law ?</h3>

This law combined the three gas laws that is (i) Charle's Law (ii) Gay-Lussac's Law and (iii) Boyle's law.

It is expressed as

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

where,

P₁ = first pressure

P₂ = second pressure

V₁ = first volume

V₂ = second volume

T₁ = first temperature

T₂ = second temperature

Now put the values in above expression we get

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

\frac{1.02\ atm \times 2.30\ L}{281\ K} = \frac{P_2 \times 1.41\ L}{298\ K}

P_{2} = \frac{1.02\ atm \times 2.30\ L \times 298\ K}{281\ K \times 1.41\ L}

P₂ = 1.76 atm

Thus from the above conclusion we can say that A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

Learn more about the Combined gas Law here: brainly.com/question/13538773

#SPJ4

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2 years ago
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Answer:

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Explanation:

because it is an allotrope of carbon

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