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katrin2010 [14]
3 years ago
7

How many cm are in 3.1 mi

Chemistry
2 answers:
Brrunno [24]3 years ago
6 0
3.1 mi translated to cm is 498896.64 (:
grandymaker [24]3 years ago
5 0
It would be 498896.64 cm
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PLS HELP Students in a chemistry class added 5 g of Zinc (Zn) to 50 g of hydrochloric acid (HCl). A chemical reaction occurred t
Vitek1552 [10]

Answer: In simplest case mass of reactants is same as mass of products.

Without thinking this question deeper, mass of ZnCl2 would be 49, but..

Explanation: Reaction should be  Zn + 2 HCl ⇒ ZnCl2 + H2

Amount of zinc is  5 g / 65,38 g/mol = 0,076476 mol and amount

of Hydrogen Chloride is 50 g / 36.458 g/mol = 1,371 mol.

Althought HCl is needed 0.152 moles, zinc is an limiting reactant.

So it is possible to produce only 0.076476 mol Hydrogen and its mass

is 0.154 g.  Mass of ZnCl2 would be 0.076476 mol · (65.38 + 2·35.45) =

 10.42 g

4 0
3 years ago
Help me out with these three formulas
ddd [48]
Carbon dioxide it should be water oxygen
7 0
4 years ago
K3PO4+AgNO3--&gt; ???<br> Ba(HCO3)2+Ba(OH2)--&gt;
GuDViN [60]

<u>Explanation:</u>

A balanced chemical equation is one where all the individual atoms are equal on both sides of the reaction. It follows the law of conservation of mass.

  • <u>For 1:</u>

When potassium phosphate reacts with silver nitrate, it leads to the formation of silver phosphate and potassium nitrate.

The balanced chemical equation follows:

3AgNO_3+K_3PO_4\rightarrow Ag_3PO_4+3KNO_3

  • <u>For 2:</u>

When barium bicarbonate reacts with calcium hydroxide, it leads to the formation of barium carbonate, calcium carbonate and water

The balanced chemical equation follows:

Ba(HCO_3)_2+Ca(OH)_2\rightarrow BaCO_3+CaCO_3+2H_2O

5 0
3 years ago
If we start with 1.000 g of strontium-90, 0.805 g will remain after 9.00 yr. This means that the of strontium-90 is ________ yr.
lesantik [10]

The question is incomplete, here is the complete question.

If we start with 1.000 g of strontium-90, 0.805 g will remain after 9.00 yr. This means that the half-life of strontium-90 is ________ yr.

a. 28.8 b. 30.9 c. 35.4 d. 32.2

Answer :  The half-life of strontium-90 is 28.8 years.

Explanation :

This is a type of radioactive decay and all radioactive decays follow first order kinetics.

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by :

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant

t = time taken for decay process  = 9.00 year

a = initial amount or moles of the reactant  = 1.000 g

a - x = amount or moles left after decay process  = 0.805 g

Putting values in above equation, we get:

k=\frac{2.303}{9.00}\log\frac{1.00}{0.805}

k=0.0241\text{ year}^{-1}

To calculate the half-life, we use the formula :

k=\frac{0.693}{t_{1/2}}

0.0241\text{ year}^{-1}=\frac{0.693}{t_{1/2}}

t_{1/2}=28.8\text{ years}

Therefore, the half-life of strontium-90 is 28.8 years.

5 0
3 years ago
What are destiny dependent factors
pochemuha

Answer:

Density dependent factors include disease, competition, and predation. Density dependant factors can have either a positive or a negative correlation to population size

Explanation:

hope this helps ;)

7 0
3 years ago
Read 2 more answers
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