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katrin2010 [14]
3 years ago
7

How many cm are in 3.1 mi

Chemistry
2 answers:
Brrunno [24]3 years ago
6 0
3.1 mi translated to cm is 498896.64 (:
grandymaker [24]3 years ago
5 0
It would be 498896.64 cm
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PLEASE HELP
Vinvika [58]

Answer:

11.6 grams of MgO can be produced with 4.63 grams of oxygen.

Explanation:

2Mg+O_2\rightarrow 2MgO

Mass of oxygen gas = 4.63 g

Moles of oxygen gas = \frac{4.63 g}{32 g/mol}=0.145 mol

According to reaction,  1 mole of oxygen gas gives 2 moles of magnesium oxide, then 0.1447 moles of oxygen gas will giv e:

\frac{2}{1}\times 0.145 mol=0.29 mol of magnesium oxide

Mass of 0.2894 moles of magnesium oxide:

= 0.29 mol × 40 g/mol = 11.6 g

11.6 grams of MgO can be produced with 4.63 grams of oxygen.

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3 years ago
Which can be used to identify an unknown substance: mass, melting point density, volume, state of matter
Akimi4 [234]
Physical properties

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mass, color, size, volume, texture, density, state of matter, boiling point, melting point

4 0
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A laser pointer used in a lecture hall emits light at 640 nm what is the frequency
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A 100.0g sample of nickel is heated to 100.0 oC (Celsius) and is placed in a coffee cup calorimeter containing 150. g of water a
Marianna [84]

Answer:

0.429 J/g.°C

Explanation:

Step 1: Calculate the heat absorbed by the water (Qw)

We will use the following expression.

Q = c × m × ΔT

where,

c: specific heat capacity

m: mass

ΔT: change in the temperature

Qw = 4.184 J/g.°C × 150. g × (29.8°C-25.0°C) = 3012 J

Step 2: Calculate the heat released by the sample of nickel

According to the law of conservation of energy, the sum of the heat lost by the sample of nickel and the heat absorbed by the water is zero.

Qw + QNi = 0

QNi = -Qw = -3012 J

Step 3: Calculate the specific heat capacity of nickel

We will use the following expression.

QNi = c × m × ΔT

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