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lana [24]
3 years ago
6

What is the ratio of the intensities and amplitudes of an earthquake P wave passing through the Earth and detected at two points

27 km and 13 km from the source?
(a) I 27 / 13 =__________
(b) A 27 / 13 =_____________-
Physics
1 answer:
gavmur [86]3 years ago
5 0

For both cases we will use the proportional values of the distance referring to the amplitude and intensity. Theoretically we know that the intensity is inversely proportional to the square of the distance, while the amplitude is inversely proportional to the distance, therefore,

PART A )  Intensity is inversely proportional to the square of the distance

Intensity \propto \frac{1}{distance^2}

Therefore the intensity of the two values would be

\frac{I_{27}}{I_{13}} = \frac{(13km)^2}{(27km)^2}

\mathbf{\therefore \frac{I_{27}}{I_{13}} = 0.232 }

PART B) Amplitude is inversely proportional to the distance

Amplitude \propto \frac{1}{distance}

\frac{A_{27}}{A_{13}}= \frac{(13km)}{(27km)}

\mathbf{\therefore\frac{A_{27}}{A_{13}}= 0.4815}

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while the distance of a point at the end of the blade from the centre is

r = 0.400 m

Therefore, the centripetal acceleration is

a=\frac{1.2^2}{0.400}=3.6 m/s^2

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