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IRINA_888 [86]
3 years ago
15

WILL GIVE BRAINLIEST!!!

Physics
2 answers:
Sergeeva-Olga [200]3 years ago
7 0
True true true true true true true true
djyliett [7]3 years ago
5 0
True true true true love
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A motorcycle of mass 100 kilograms travels around a flat, circular track of radius 10 meters with a constant speed of 20 meters
JulijaS [17]

Answer:

100/10 = 10 , 10 × 10 = 100÷20 = 5

I'm pretty sure its wrong

8 0
3 years ago
Read 2 more answers
A firefighter of mass 81 kg slides down a vertical pole with an acceleration of 3 m/s 2 . The acceleration of gravity is 10 m/s
natima [27]

Answer:

The force of friction that acts on him is

F_k=567N

Explanation:

The firefighter with an acceleration of 3m/s^2 take the gravity acceleration as 10m/s^2 isn't necessary to know the coefficient of friction just to know the force of friction:

F=m*a

F=F_w-F_k

m*a=F_w-F_k

F_w=81kg*10m/s^2=810N

Sole to Fk

81kg*3m/s^2=810N-F_k

F_k=810N-243N

F_k=567N

4 0
2 years ago
What is primary sex organs called
Ostrovityanka [42]
The primary sex organs for men are called testes and ovaries for the women. They produce sex cells called gametes and they secrete sex hormones.
6 0
3 years ago
Read 2 more answers
What volume of water has the same mass as 1.5 L of gasoline?
Ivahew [28]
Based on the options given, the possible answer for this query is 0.450g/450kg
density of water is = 1 g/cm3density of gasoline is = 0.7 g/cm3difference is .3 g/cm3

d=m/v
derivation: m=dv
=.450 g/450kgThank you for your question. Please don't hesitate to ask in Brainly your queries. 
8 0
2 years ago
A soap bubble, when illuminated at normal incidence with light of 463 nm, appears to be especially reflective. If the index of r
Sedbober [7]

Answer:

the minimum thickness the soap film can be if it is surrounded by air is 85.74 nm

Explanation:

Given the data in the question;

wavelength of light; λ = 463 nm = 463 × 10⁻⁹ m

Index of refraction; n = 1.35

Now, the thinnest thickness of the soap film can be determined from the following expression;

t_{min = ( λ / 4n )

so we simply substitute in our given values;

t_{min = ( 463 × 10⁻⁹ m ) / 4(1.35)

t_{min = ( 463 × 10⁻⁹ m ) / 5.4

t_{min = ( 463 × 10⁻⁹ m ) / 4(1.35)

t_{min = 8.574 × 10⁻⁸ m

t_{min = 85.74 × 10⁻⁹ m

t_{min = 85.74 nm

Therefore, the minimum thickness the soap film can be if it is surrounded by air is 85.74 nm

5 0
2 years ago
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