A 2000-kg railway freight car coasts at 4.4 m/s underneath a grain terminal, which dumps grain directly down into the freight ca
1 answer:
Answer:
933. 3kg
Explanation:
We are given that
Mass,m=2000 kg
Initial speed,u=4.4 m/s
We have to find the maximum mass of grain if the speed of loaded freight car must not go below 3.0 m/s.
Final speed,v=3 m/s
By conservation of momentum
Initial momentum=Final momentum
Substitute the values
Mass of freight loaded car=2933.3 kg
Mass of grains=2933.3-2000=933.3 kg
Hence, the maximum mass of grains that it can accept=933.3 kg
You might be interested in
Answer:
Explanation:
There is electric field between the plates whose value is given by the following expression
electric field E = V /d where V is potential between the plates and d is distance between them
E = 300 / 5 x 10⁻³
= 60 x 10³ N/c
Force on electron = q E where q is charge on the electron
F = 1.6 X 10⁻¹⁹ X 60 X 10³ = 96 X 10⁻¹⁶ N.
Acceleration a = force / mass
a = 96 x 10⁻¹⁶/ mass = 96 x 10⁻¹⁶ / 9.1 x 10⁻³¹
= 10.55 x 10¹⁵ m / s²
For midway , distance travelled
s = 2.5 x 10⁻³ m
s = 1\2 a t²
t =
=
t = .474 x 10⁻¹⁸ s
For striking the plate time is calculated as follows
t = [/tex]
t = 0.67 x 10⁻¹⁸ s