All categories

3 years ago

What percent of earth's density does Jupiter have?

1 answer:

Ivan3 years ago

3 0

Density of Earth: 5.514 g/cm³
Density of Jupiter: <span>1.326 g/cm³

1.326 g/cm³ / 5.514 g/cm³ </span>≈ <span>0,24
0,24 * 100 = 24%

Jupiter has 24% of earth's density.

(Density numbers are from internet, you may calculate with your own ones if u have )</span>

You might be interested in

An airplane flies 1,592 miles east from phoenix, Arizona, to Atlanta, Georgia, in 3.68 hours. What is the average velocity of th

KiRa [710]

Answer:

433 mph

Explanation:

We know that

$Velocity =\frac{Distance}{Time }$ ...Eq(1)

Here,

Distance =1,592 miles

Time=3.68 hours

Putting the value of distance and Time in the Eq(1) We get

Velocity = $\frac{1592\ miles}{3.68\ hours}$

$Velocity = 432.608\ mph\\Velocity = 433 mph$

therefore Average velocity is 433 mph

3 0

3 years ago

If a particle with a charge of +4.3 × 10−18 C is attracted to another particle by a force of 6.5 × 10−8 N, what is the magnitude

AveGali [126]

Answer: 1.5×10^10 N/C

Explanation:

E= F/q

Where E= magnitude of the electric field

F= force of attraction

q= charge of the given body

Given F= 6.5×10^-8 N

q= 4.3× 10^-18 C

Therefore, E = 6.5×10 ^-8/ 4.3×10^-18

E = 1.5×10^10 N/C

7 0

3 years ago

An object with a 25 µC charge is 0.54 m away from a second charged object. They experience a force of 3250 N. What is the charge

nekit [7.7K]

25 uc charge is 0.54 m away

6 0

2 years ago

A uniform disk with a 25 cm radius swings without friction about a nail through the rim. If it is released from rest from a posi

ValentinkaMS [17]

Answer:

Explanation:

During the swing , the center of mass will go down due to which disc will lose potential energy which will be converted into rotational kinetic energy

mgh = 1/2 I ω² where m is mass of the disc , h is height by which c.m goes down which will be equal to radius of disc , I is moment of inertia of disc about the nail at rim , ω is angular velocity .

mgr = 1/2 x ( 1/2 m r²+ mr²) x ω²

gr = 1/2 x 1/2 r² x ω² + 1/2r² x ω²

g = 1 / 4 x ω² r + 1 / 2 x ω² r

g = 3 x ω² r/ 4

ω² = 4g /3 r

= 4 x 9.8 / 3 x .25

= 52.26

ω = 7.23 rad / s .

6 0

3 years ago

You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headligh

spayn [35]

To solve this problem we will apply the concepts related to Reyleigh's criteria. Here the resolution of the eye is defined as 1.22 times the wavelength over the diameter of the eye. Mathematically this is,

$\theta = \frac{1.22 \lambda }{D}$