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3 years ago

What percent of earth's density does Jupiter have?

1 answer:

Ivan3 years ago

3 0

Density of Earth: 5.514 g/cm³
Density of Jupiter: <span>1.326 g/cm³

1.326 g/cm³ / 5.514 g/cm³ </span>≈ <span>0,24
0,24 * 100 = 24%

Jupiter has 24% of earth's density.

(Density numbers are from internet, you may calculate with your own ones if u have )</span>

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White raven [17]

Answer:

The direction of defliection of the site to the left I think ..

4 0

2 years ago

An ideal gas occupies 0.4 m3 at an absolute pressure of 500 kPa. What is the absolute pressure if the volume changes to 0.9 m3 a

sveticcg [70]

Answer:

Explanation:

The new volume can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we are finding the new volume

$V_2 = \frac{P_1V_1}{P_2} \\$

From the question we have

$V_2 = \frac{0.4 \times 500000}{0.9} = \frac{200000}{0.9} \\ = 222222.2222... \\ = 222222$

We have the final answer as

Hope this helps you

5 0

2 years ago

The mass of an object was measure on a balance and reported as 65.35g and it displaced 3.4ml. What is the density of the object

Sindrei [870]

Answer:

your [email protected] father

Explanation:

5 0

3 years ago

Adoption process of the SI system by all the worlds nations is called

Licemer1 [7]

Adoption process of the SI system by all the worlds nations is called Metrication or metrification.

Metrication or metrification is defined as conversion to the metric system of units of measurement. Earlier, many traditional and local systems were used for conversion but since last 2 centuries, most of the countries have adopted the SI system that is widely used as system of measurement.

6 0

3 years ago

A rocket with a total mass of 330,000 kg when fully loaded burns all 280,000 kg of fuel in 250 s. The engines generate 4.1 MN of

lutik1710 [3]

Answer:

6900 m/s

Explanation:

The mass of the rocket is:

m = 330000 − 280000 (t / 250)

m = 330000 − 1120 t

Force is mass times acceleration:

F = ma

a = F / m

a = F / (330000 − 1120 t)

Acceleration is the derivative of velocity:

dv/dt = F / (330000 − 1120 t)

dv = F dt / (330000 − 1120 t)

Multiply both sides by -1120:

-1120 dv = -1120 F dt / (330000 − 1120 t)

Integrate both sides. Assuming the rocket starts at rest:

-1120 (v − 0) = F [ ln(330000 − 1120 t) − ln(330000 − 0) ]

-1120 v = F [ ln(330000 − 1120 t) − ln(330000) ]

1120 v = F [ ln(330000) − ln(330000 − 1120 t) ]

1120 v = F ln(330000 / (330000 − 1120 t))

v = (F / 1120) ln(330000 / (330000 − 1120 t))

Given t = 250 s and F = 4.1×10⁶ N:

v = (4.1×10⁶ / 1120) ln(330000 / (330000 − 1120×250))

v = 6900 m/s

4 0

3 years ago