Answer:
15.0 L
Explanation:
To find the volume, you need to use the Ideal Gas Law:
PV = nRT
In this equation,
-----> P = pressure (mmHg)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas constant (62.36 L*mmHg/mol*K)
-----> T = temperature (K)
To calculate the volume, you need to (1) convert grams C₄H₁₀ to moles (via the molar mass), then (2) convert the temperature from Celsius to Kelvin, and then (3) calculate the volume (via the Ideal Gas Law).
Molar Mass (C₄H₁₀): 4(12.011 g/mol) + 10(1.008 g/mol)
Molar Mass (C₄H₁₀): 58.124 g/mol
32 grams C₄H₁₀ 1 moles
------------------------- x ----------------------- = 0.551 moles C₄H₁₀
58.124 grams
P = 728 mmHg R = 62.36 L*mmHg/mol*K
V = ? L T = 45.0 °C + 273.15 = 318.15 K
n = 0.551 moles
PV = nRT
(728 mmHg)V = (0.551 moles)(62.36 L*mmHg/mol*K)(318.15 K)
(728 mmHg)V = 10922.7632
V = 15.0 L
Answer: a
Explanation:
Industry uses only about 18% while the others use around 70-90% of water.
YW!!! please mark branlest!!!! =^.^=
It is more slippery, and it is heavier
<h3>
Answer:</h3>
12.387 moles
<h3>
Explanation:</h3>
We are given;
Temperature of chlorine, T = 120°C
But, K = °C + 273.15
Therefore, T = 393.15 K
Pressure, P = 33.3 Atm
Volume, V = 12 L
We are required to calculate the number of moles of chlorine gas,
To find the number of moles we are going to use the ideal gas equation;
PV = nRT
R is the ideal gas constant, 0.082057 L.atm/mol.K
Therefore, rearranging the formula;
n = PV÷RT
Hence;
n = (33.3 atm × 12 L) ÷ (0.082057 × 393.15 K)
= 12.387 moles
Therefore, the number of moles of chlorine are 12.387 moles
