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3 years ago

What is energy? Give at least two examples of how you use energy in your everyday life.

Chemistry

2 answers:

Marrrta [24]3 years ago

7 0

The capability or ability to do work is called energy

scZoUnD [109]3 years ago

3 0

Answer:

To walk or run, and to wake up.

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How does the density of ice compare with that of liquid water? What evidence can you cite to support your answer?

SpyIntel [72]

Answer: Ice is less dense than water.

Explanation: As water freezes, it expands, making it less dense. This is why ice cubes float in a glass of water.

6 0

3 years ago

A 2.241-g sample of nickel reacts with oxygen to form 2.852 g of the metal oxide.

nlexa [21]

Answer:

The empirical formula is = $NiO$

Explanation:

Given that:- Mass of nickel = 2.241 g

Mass of the oxide formed = 2.852 g

Mass of the oxygen reacted = Mass of the oxide formed - Mass of nickel = 2.852 g - 2.241 g = 0.611 g

Molar mass of nickel = 58.6934 g/mol

Moles of nickel = $\frac{2.241}{58.6934}\ mol$ = 0.03818 mol

Molar mass of oxygen = 15.999 g/mol

Moles of nickel = $\frac{0.611}{15.999}\ mol$ = 0.03818 mol

Taking the simplest ratio for Ni and O as:

0.03818 : 0.03818 = 1 : 1

The empirical formula is = $NiO$

4 0

4 years ago

0.456 grams of a monoprotic acid is titrated with 45.88 mL of 0.0500 M NaOH. What is the molecular mass (molar mass) of the acid

aivan3 [116]

Answer:

$Molar\ mass= 198.78\ g/mol$

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Given :

For NaOH :

Molarity = 0.0500 M

Volume = 45.88 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 45.88×10⁻³ L

$Moles_{NaOH} =0.0500 \times {45.88\times 10^{-3}}\ moles=0.002294\ moles$

Moles of NaOH = Moles of monoprotic acid

So, moles of monoprotic acid = 0.002294 moles

Given that:- mass = 0.456 g

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$0.002294\ moles= \frac{0.456\ g}{Molar\ mass}$

$Molar\ mass= 198.78\ g/mol$

3 0

3 years ago

An air/gasoline vapor mix in an automobile cylinder has an initial temperature of 180 ∘C and a volume of 13 cm3 . If the mixture

earnstyle [38]

Answer:

The final volume will be 24.7 cm³

Explanation:

Step 1: Data given:

Initial temperature = 180 °C

initial volume = 13 cm³ = 13 mL

The mixture is heated to a fina,l temperature of 587 °C

Pressure and amount = constant

Step 2: Calculate final volume

V1/T1 = V2/T2

with V1 = the initial volume V1 = 13 mL = 13*10^-3

with T1 = the initial temperature = 180 °C = 453 Kelvin

with V2 = the final volume = TO BE DETERMINED

with T2 = the final temperature = 587 °C = 860 Kelvin

V2 = (V1*T2)/T1

V2 = (13 mL *860 Kelvin) /453 Kelvin

V2 = 24.68 mL = 24.7 cm³

The final volume will be 24.7 cm³

5 0

3 years ago

Cu2(s)+O2(g)=Cu2O(g)+SO2(g) please help urgent will give brainiest

AysviL [449]

Answer:

2 Cu2S + 3 O2 = 2 Cu2O + 2 SO2

Explanation:

2 Cu2S + 3 O2 = 2 Cu2O + 2 SO2

3 0

3 years ago