I read and said it's a weak base
I think the correct answer from the choices listed above is option D. The net ionic equation that will describe the reaction of the reactants when mixed is expressed as:
<span>2PO43–(aq) + 3Ca2+(aq) → Ca3(PO4)2(s)
</span>
Hope this answers the question. Have a nice day.
Answer:
1.8 × 10² s
Explanation:
Let's consider the reduction that occurs upon the electroplating of copper.
Cu²⁺(aq) + 2 e⁻ ⇒ Cu(s)
We will establish the following relationships:
- 1 g = 1,000 mg
- The molar mass of Cu is 63.55 g/mol
- When 1 mole of Cu is deposited, 2 moles of electrons circulate.
- The charge of 1 mole of electrons is 96,486 C (Faraday's constant).
- 1 A = 1 C/s
The time that it would take for 336 mg of copper to be plated at a current of 5.6 A is:
![336mgCu \times \frac{1gCu}{1,000mgCu} \times \frac{1molCu}{63.55gCu} \times \frac{2mole^{-} }{1molCu} \times \frac{94,486C}{1mole^{-}} \times \frac{1s}{5.6C} = 1.8 \times 10^{2} s](https://tex.z-dn.net/?f=336mgCu%20%5Ctimes%20%5Cfrac%7B1gCu%7D%7B1%2C000mgCu%7D%20%5Ctimes%20%5Cfrac%7B1molCu%7D%7B63.55gCu%7D%20%5Ctimes%20%5Cfrac%7B2mole%5E%7B-%7D%20%7D%7B1molCu%7D%20%5Ctimes%20%5Cfrac%7B94%2C486C%7D%7B1mole%5E%7B-%7D%7D%20%5Ctimes%20%5Cfrac%7B1s%7D%7B5.6C%7D%20%3D%201.8%20%5Ctimes%2010%5E%7B2%7D%20s)