1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
salantis [7]
3 years ago
13

Mary and her younger brother Alex decide to ride the carousel at the State Fair. Mary sits on one of the horses in the outer sec

tion at a distance of 2.0 m from the center. Alex decides to play it safe and chooses to sit in the inner section at a distance of 1.0 m from the center. The carousel takes 3.7 s to make each complete revolution.
a) What is Mary's angular speed %u03C9M and tangential speed vM?

b) What is Alex's angular speed %u03C9A and tangential speed vA?
Physics
1 answer:
Alex3 years ago
7 0

Answer:

ωM = 1.7 rad/s

vM = 3.4 m/s

ωA = 1.7 rad/s

vA =  1.7  m/s

Explanation:

Calculation of the angular speed (ω)

We use the following formula for circular motion:

ω = θ / t Formula (1)

Where:

ω: angular speed (rad/s)

θ:angle that the particle travels (rad)

t: time interval (s)

Equivalence

1 revolution = 2π rad

Data

θ= 1 revolution = 2π rad

t = 3.7 s

We replace data in the formula (1):

ω = (2π rad) / (3.7s )= 1.7 rad/s

Because the angular speed depends only on the number of turns in a time interval then Mary's angular speed (ωM) is equal to Alex's angular speed (ωA).

ωM = ωA = 1.7 rad/s

Calculation of the  tangential speed (v)

We use the following formula for circular motion:

v = ω*r  Formula (2)

Where:

v : tangential speed (m/s)

ω: angular speed ( rad/s)

r  : radius of the circular path (m)

Data

ωM = ωM = ω= 1.7 rad/s

rM = 2m  : Mary's circular path radius

rA = 1m :  Alex's circular path radius

We apply the formula (2) to calculate v:

vM = ω* rM = (1.7) (2) = 3.4 m/s

vA = ω* rA = (1.7) (1) =  1.7  m/s

You might be interested in
A submarine is stranded on the bottom of the ocean with its hatch 21.0 m below the surface. calculate the force (in n) needed to
Tanzania [10]

Answer:

28,400 N

Explanation:

Let's start by calculating the pressure that acts on the upper surface of the hatch. It is given by the sum of the atmospheric pressure and the pressure due to the columb of water, which is given by Stevin's law:

p_{top} = p_{atm} + \rho g h=1.013\cdot 10^5 Pa + (1000 kg/m^3)(9.8 m/s^2)(21.0 m)=3.071 \cdot 10^5 Pa

On the lower part of the hatch, there is a pressure equal to

p_{bot}=p_{atm}=1.013\cdot 10^5 Pa

So, the net pressure acting on the hatch is

p=p_{top}-p_{bot}=3.071 \cdot 10^5 Pa - 1.013\cdot 10^5 Pa=2.058 \cdot 10^5 Pa

which acts from above.

The area of the hatch is given by:

A=\pi r^2 = \pi (\frac{0.420 m}{2})^2=0.138 m^2

So, the force needed to open the hatch from the inside is equal to the pressure multiplied by the area of the hatch:

F=pA=(2.058\cdot 10^5 Pa)(0.138 m^2)=28,400 N

8 0
3 years ago
The direction of an electric field is always in the direction _______________ would naturally move.
Masja [62]

Answer:

Im not really sure but Id say weather .

Explanation:

6 0
3 years ago
The velocity of an object is equal to the distance divided by time. The equation is velocity = distance/time. If you wanted to c
Korolek [52]

Answer: C) divide: distance ÷ velocity

Explanation:

The velocity V equation is distance d divided by time t:

V=\frac{d}{t}

If we isolate t we will have:

t=\frac{d}{V}

Hence, the correct option is C: distance divided by velocity.

7 0
3 years ago
3. Imagine a 10kg block moving with a speed of 20m/s<br> calculate the kinetic energy of this block
MatroZZZ [7]
The formula of the kinetic energy is:
E_{k}  =  \frac{m v^{2} }{2}
where m is a mass of the object, v is speed of the object at the moment of time. So we have:
E_{k}  =  \frac{10* 20^{2} }{2}  = 2000J
The answer is 2000 Joules.
6 0
3 years ago
a slender rod of mass m and length l is released from rest in a horizontal position. what is the rod's angular velocity when it
Makovka662 [10]

Answer:

M g H / 2 = M g L / 2      initial potential energy of rod

I ω^2 / 2 = 1/3 M L^2 * ω^2 / 2   kinetic energy attained by rod

M g L / 2 = 1/3 M L^2 * ω^2 / 2

g = 3 L ω^2

ω = (g / (3 L))^1/2

8 0
2 years ago
Other questions:
  • how much energy is required to turn 20 gram cube of ice at a temperature of -10 degrees Celsius into liquid water at a temperatu
    10·1 answer
  • Turning a vector to a scalar is possible ???​
    5·1 answer
  • The radar system of a navy cruiser transmits at a wavelength of 2.0 cm, from a circular antenna with a diameter of 2.0 m. At a r
    10·1 answer
  • Two forces F1 and F2 act on a 5.00 kg object. Taking F1=20.0N and F2=15.00N, find the acceleration of the object for the configu
    5·2 answers
  • Question 2 please need help physics
    10·1 answer
  • During the first 14 minutes of a 1.0 hour trip, a car has an average speed 36 km/h. What must the average speed in km/h of the c
    11·1 answer
  • A spring scale can be used on
    10·2 answers
  • Total mechanical energy (The sum of kinetic and potential energy
    13·1 answer
  • While driving his 600-kg ultra-compact electric car, a distracted driver starts crossing a drawbridge. Not realizing that the dr
    7·1 answer
  • You matter .<br>Until you Multiply yerself by the speed of Light Squared. <br>Then you Energy.<br>​
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!