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tangare [24]
3 years ago
14

Carbon and hydrogen are examples of pure substances or

Physics
2 answers:
Ede4ka [16]3 years ago
7 0
The are elements on the periodic table
Softa [21]3 years ago
4 0

Answer:

Elements

Explanation:

Carbon and Hydrogen are pure substances or elements. All the atoms of carbon have same number of protons. It cannot be broken into new elements.

Contrary to elements, there are compounds which are formed by the chemical bonds between two or more elements like in water. In water, Hydrogen and oxygen elements combine. All the atoms of water do not have the same number of protons. Then, there are mixtures where elements are not chemically bound. For example, air.

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kondor19780726 [428]

Answer:

1. b

2. c

3. b

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7 0
3 years ago
ASAP! State the direction of<br> the oscillation of a<br> longitudinal wave??<br> Worth 40 P! ASAP!
Liula [17]

In a longitudinal wave the particle displacement is parallel to the direction of wave propagation. ... The particles do not move down the tube with the wave; they simply oscillate back and forth about their individual equilibrium positions.Answer:

Explanation:

7 0
3 years ago
a lawn mower is pushed with a force of 50n. if the angle between the handle of the mower and the ground is 30°. why doesn't the
Mademuasel [1]

Answer:

IT doesnt push down because the lawnmower has wheels and the ground is hard

Explanation:

Branliest

5 0
3 years ago
f the pressure of a sample of gas is doubled at constant temperature, what happens to the volume of the gas?
vaieri [72.5K]

it is halved.

p1v1=p2v2

2p1x1/2xv1=p1v1

4 0
3 years ago
Block A of mass M is on a horizontal surface of negligible friction. An identical block B is attached to block A by a light stri
miv72 [106K]

Answer:

T’= 4/3 T  

The new tension is 4/3 = 1.33 of the previous tension the answer e

Explanation:

For this problem let's use Newton's second law applied to each body

Body A

X axis

      T = m_A a

Axis y

     N- W_A = 0

Body B

Vertical axis

     W_B - T = m_B a

In the reference system we have selected the direction to the right as positive, therefore the downward movement is also positive. The acceleration of the two bodies must be the same so that the rope cannot tension

We write the equations

    T = m_A a

    W_B –T = M_B a

We solve this system of equations

     m_B g = (m_A + m_B) a

    a = m_B / (m_A + m_B) g

In this initial case

     m_A = M

     m_B = M

     a = M / (1 + 1) M g

     a = ½ g

Let's find the tension

    T = m_A a

    T = M ½ g

    T = ½ M g

Now we change the mass of the second block

    m_B = 2M

    a = 2M / (1 + 2) M g

    a = 2/3 g

We seek tension for this case

    T’= m_A a

    T’= M 2/3 g

   

Let's look for the relationship between the tensions of the two cases

   T’/ T = 2/3 M g / (½ M g)

   T’/ T = 4/3

   T’= 4/3 T

The new tension is 4/3 = 1.33 of the previous tension the answer  e

4 0
3 years ago
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