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ivanzaharov [21]

3 years ago

10

Why do specific heat capacity of objects differ ?

2 answers:

vladimir2022 [97]3 years ago

5 0

Explanation:

<em>Each substance will have a different mass, so when the amount of heat and the change in temperature are held constant, the only variable is the mass. Therefore, because mass is the only variable, so because substances have different masses, they will have different specific heats</em><em>.</em><em> </em>

kirill115 [55]3 years ago

4 0

Answer:

substances have different melting and boiling points to one another.

Explanation:

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A third point charge q3 is now positioned halfway between q1 and q2. The net force on q2 now has a magnitude of F2,net = 4.444 N

Dmitriy789 [7]

Answer:

The value of third charge is 0.8μC.

Explanation:

Given that.

Magnitude of net force=4.444 N

According to figure,

Suppose, First charge = 2.4 μC

Second charge = 6.2 μC

Distance r₁ = 9.8 cm

Distance r₂ = 2.1 cm

We need to calculate the value of r

Using Pythagorean theorem

$r=\sqrt{(r_{1})^2+(r_{2})^2}$

Put the value into the formula

$r=\sqrt{(9.8)^2+(2.1)^2}$

$r=10.02\ cm$

We need to calculate the force

Using formula of force

$F_{12}=\dfrac{kq_{1}q_{2}}{(r)^2}$

Force F₁₂,

$F_{12}=\dfrac{9\times10^{9}\times2.4\times10^{-6}\times6.2\times10^{-6}}{(10.02\times10^{-2})^2}$

$F_{12}=13.33\ N$

$F_{21}=-13.33\ N$

Force F₂₃,

$F_{23}=\dfrac{9\times10^{9}\times6.2\times10^{-6}\times q_{3}}{(10.02)^2}$

We need to calculate the value of third charge

$F_{net}=F_{21}+F_{23}$

$4.444=-13.33+\dfrac{9\times10^{9}\times6.2\times10^{-6}\times q_{3}}{(5.01)^2}$

$q_{3}=\dfrac{(4.444+13.33)\times(5.01\times10^{-2})^2}{9\times10^{9}\times6.2\times10^{-6}}$

$q_{3}=7.99\times10^{-7}\ C$

$q_{3}=0.8\times10^{-6}\ C$

Hence, The value of third charge is 0.8μC.

4 0

3 years ago

Is cutting a string physcal or chemical change

oksano4ka [1.4K]

This is a physical change because cutting the string didn't change it chemically, but it did physically.

6 0

3 years ago

A proposed answer to a scientific problem is a _.

liubo4ka [24]

Answer:

A proposed answer to a s scientific problem is a hypothesis.

7 0

2 years ago

Could I get some help with this

nika2105 [10]

please give me brainlest!!

the answer is A.

4 0

3 years ago

Encuentre en km.h la velocidad de un tigre que corre 550 km.h en 69min

Len [333]

Answer:

v = 478.26 km/h

Explanation:

The question is "find in km.h the speed of a tiger that runs 550 km in 69min"

Distance, d = 550 km

Time, t = 69 min = 1.15 h

We need to find the speed of the tiger. The speed of an object is equal to the total distance covered divided by time taken. So,

$v=\dfrac{550\ km}{1.15\ h}\\\\v=478.26\ km/h$

So, the speed of the tiger is 478.26 km/h.

8 0

3 years ago